99,990.
90. All numbers divisible by 5 and 9 are multiples of their lowest common multiple. lcm(5, 9) = 45 → need an even two digit multiple of 45, which is 2 x 45 = 90.
A 5-digit number that is divisible by 9 must have its digits sum to a multiple of 9. The smallest 5-digit number that fits this criterion is 10,008 (1 + 0 + 0 + 0 + 8 = 9). Other examples include 10,017, 10,026, and so on, up to the largest 5-digit number that is divisible by 9, which is 99,999.
If the number is divisible by both 5 and 9, then the number fits into 45 perfectly. 5- If the last digit is 0 or 5 9- If the sum of the digits are divisible by 9 Examples: 61,335, 844,560, 174,555 Non Examples: 4,122, 2085
45/5 = 9 45/9 = 5 Therefore, the smallest number divisible by both numbers is 45.
Any number that ends with the digit 5 is divisible by 5.Any number that ends with the digit 5 is divisible by 5.Any number that ends with the digit 5 is divisible by 5.Any number that ends with the digit 5 is divisible by 5.
99,990.
999990
You just need a 4 digit number divisible by 5x9 ie by 45, so 4500 will do.
Here are all of them: 18, 27, 36, 45, 54, 63, 72, 81, 90 and 99.
The lowest common multiple of 5 and 9 is 45 and 11 times 45 is 495 which is the greatest 3 digit number divisible by 5 and 9
Because 90 is the first number that is divisible by both 45 and 18.
A number is divisible by 9 if the sum of its digits is divisible by 9. Thus, the number 99999 is divisible by 9 (the sum of its digits is 45, and it is clearly 11111 * 9), and because 99999 is the largest 5 digit number, it must be the largest 5 digit multiple of 9. 99999 is the greatest no divisible by 9.if u divide it u`ll get 11111.
To find the greatest 3-digit number divisible by both 5 and 9, we need to find the highest common multiple of 5 and 9 within the range of 100 to 999. The highest common multiple of 5 and 9 is 45. To find the greatest 3-digit number divisible by 45, we divide 999 by 45, which equals 22 with a remainder. Therefore, the greatest 3-digit number divisible by both 5 and 9 is 45 x 22 = 990.
Count by 45. 45,90,135,180 so you have two choices.
90. All numbers divisible by 5 and 9 are multiples of their lowest common multiple. lcm(5, 9) = 45 → need an even two digit multiple of 45, which is 2 x 45 = 90.
A 5-digit number that is divisible by 9 must have its digits sum to a multiple of 9. The smallest 5-digit number that fits this criterion is 10,008 (1 + 0 + 0 + 0 + 8 = 9). Other examples include 10,017, 10,026, and so on, up to the largest 5-digit number that is divisible by 9, which is 99,999.