Q: A bus travels 10 miles south 4 miles west 2 miles north and 1 mile west Finally it goes 8 miles north how many miles is the bus from the starting point?

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That is incorrect. The distance travelled north cancels out the distance travelled south. Therefore - he only travels three blocks east.

Speed = Distance divided by Time. So, speed = 75 miles divided by 2.5 hours = 75 / 2.5 = 30 miles per hour. Velocity is speed and direction, so the velocity is 30 mph Northbound.

Plane A travels due north at 150 mph for 2 hours, it will go 300 miles. Plane B travels due west at 200 mph for 2 hours, it will go 400 miles. Draw the two vectors and you will see that they make two sides of a right triangle. The distance between the two planes at the end of two hours is just the hypotenuse of this triangle. You could use the Pythagorean theorem (c^2 = a^2 + b^2) to find the distance...or you could recognise that 300 and 400 are two of a pythagorean triplet (300, 400, 500) and the third number of this triplet is 500. So, the planes will be 500 miles aprt at the end of two hours

20 miles per hour north is an example of

3.00 m/s

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25 miles.

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This is a question based on Pythagoras. The answer is sqrt[(15)2 + (20)2] = 25 miles

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This is where you apply the pythagorean theorem: d = √(152 + 202) ∴d = √(225 + 400) ∴d = √(625) ∴d = 25 So the boat is 15 miles from it's starting point

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A trick question! The boat is still quite close to the point where it dropped the anchor! ============================ The boat is approximately 25 miles from its starting point, and exactly zero miles from the point where the anchor was dropped.

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The displacement is square root of (4^2 + 2^2)= sqrt(20)= 2 sqrt(5)