This can be solved by expressing parts of the number separately.
You already know that the last digit of your starting number is 4. You also know that if you take that last digit, and move it to the front of the number, the result is four times the original number. What we don't know is how many digits the rest of the number is, or what it's value is. For now, let's call those remaining digits "A".
In that case, we can say that our original number is 10A + 4, and our resulting number is 4 × 10x + A where x is the number of digits used in the number A.
We also know that our resulting number is four times the value of the first one, and with that we can assemble the equation:
4(10A + 4) = 4 × 10x + A
and simplify it:
∴40A + 16 = 4 × 10x + A
∴39A = 4 × 10x - 16
∴A = (4 × 10x - 16) / 39
All we have to do now is try different values of x until we find one that results in A being an integer value.
Let's see if we can do that with a two digit number:
A = (4 × 102 - 16) / 39
∴ A = (400 - 16) / 39
∴ A = 384 / 39
Of course that doesn't actually work, because it gives us a fraction. We may have to go through several numbers before we find one that works, but that can be done pretty quickly. We just need to add a zero to our multiple of 4, and keep testing until we find one that gives us an integer:
(4000 - 16) / 39 = 3984 / 39 ≈ 102.15
(40000 - 16) / 39 = 39984 / 39 ≈ 1025.23
(400000 - 16) / 39 = 399984 / 39 = 10256
And there we have the number we want. A is equal to 10256, and we can now say that the original number we're looking for is:
102564
And if we test it to be sure:
102564 × 4 = 410256
We can see that this does indeed work.
Ans. 102,564 (102,564 x 4 = 410,256)
The number ends in a 4 so multiplying by 4 makes the next figure to the left a 6 with 1 to carry. (64)
Multiplying the 6 by 4 and adding the carry makes the next figure 5 with 2 to carry. (564)
Since (4x5) +2 =22, the next is 2 with 2 to carry. (2564)
(2x4)+2 =10, so place 0 and carry 1 (02564)
(0x4)+1=1, so place the 1, with no carry. (102564)
No, Infinity is never ending, where as a googolplex is a fixed number.
The larger number is 48: it was 40.
No, that will indicate the percentage the smaller number is of the larger number.
0.19 is the larger number
065 is just another way to write 65 but in 3 digits. if a 0 is in front of a number it means nothing. If it is behind a number, it becomes larger such as 650. ________________________ Answer to your Question: 065 = 65
6
No, Infinity is never ending, where as a googolplex is a fixed number.
Atomic number is reduced by one.So a proton has removed.
No. Proof: A number ending in 6 is divisible by 2, The only prime number divisible by 2 is 2 itself. A number ending in 6 is larger than 2.
The larger number is 48: it was 40.
An atom that gains or loses electrons becomes an ion. NOTE: if the number of electrons becomes more than the number of protons, then it becomes a negatively charged particle (anion) and if the protons becomes larger than the number of electrons, the atom becomes a positively charged particle (cation).
The number 6. When 6 is turned upside down, it becomes 9. 9>6.
As long as the whole number is not zero, it becomes a unit fraction with a larger denominator, ie one with a smaller value.
44.49 is more precise than 44.5 but less precise than 44.491 - The larger a number becomes the more precise it is.
Multiply it by a number that is large enough so that the numerator of the fraction becomes larger than its denominator.
That is because primality is not defined for 0. Any larger number ending in 0 is divisible by 10 and so cannot be prime.
let x be the smaller number. let x + 2 be the larger number. 4 times the smaller number is 2 more than 3 times the larger number. in equation form, this becomes: 4x = 3 * (x+2) + 2 simplify this to get: 4x = 3x + 6 + 2 which becomes: 4x = 3x + 8 subtract 3x from both sides of this equation to get: x = 8