Not that it matters anymore since this was posted so long ago.. but the answer is 4-17i. Not sure why exactly. I just decided that maybe if I were to change the sign to negative, maybe it would work, which it did! Yes, I am smart. No need to thank me.
There are infinitely many polynomials which meet the requirement.The polynomial is x2 + (-a - bi - 3)x + (2a - 2bi - ai + b) = 0and the other root is x = a + bi.There is nothing in the question which requires its coefficients to be real.
The degree of this polynomial is 2.
yes, and it is 14x
2048
It is 6.
4-17i
There are infinitely many polynomials which meet the requirement.The polynomial is x2 + (-a - bi - 3)x + (2a - 2bi - ai + b) = 0and the other root is x = a + bi.There is nothing in the question which requires its coefficients to be real.
False
A fifth degree polynomial.
The actual equation itself is the polynomial. There is no polynomial for it, and your question doesn't really make sense.
It is a quadratic polynomial.
7X^3 Third degree polynomial.
what kind of polynomial is shown 3x3+x+1
F(x) = 15x2 - 2.5 + 3 That's a quadratic or 2nd degree polynomial in x.
The degree of this polynomial is 2.
Both - a polynomial expression, if you like.
Fibonacci numbers