Perimeter = sum of the sides
An octogan has 8 sides
P = 32 cm x 8 Sides
P = 256 cm
If it's a regular octagon, the perimeter is 8 times the length of one side.
It depends how big it is. But the rule is: Side length x 8 = Perimeter. For example, if one side was eleven centimeters long then the perimeter would be P= 11 x 8. It would be eighty-eight centimeters. Note: This rule only works for regular octagons. If you need to find the perimeter of an irregular octagon, then you have to measure each side and add up the measurements of each side.
The perimeter is 72.
8 sides on an octagon. 1 cmis equal to10mm. Therefor, 10 x 8= 80 mm
112 inches, that is if all the sides are the same length .I think.
8
64 in.
If a regular octagon has a perimeter of 40cm, then each side is 5 cm.
To find the length of each side of a regular octagon with a perimeter of 56, we divide the perimeter by the number of sides. Since an octagon has 8 sides, we divide 56 by 8 to get 7. Therefore, each side of the regular octagon is 7 units long.
If the octagon is not regular, the perimeter could have any value greater than 18 inches. If it is regular, then the perimeter is 8*18 = 144 inches.
If the permiter of a regular octagon is 8z-16, then the length of each side would be the perimeter / 8 or 2z-2
Octagon has 8 side. Total perimeter is 208 mm, hence each side = 208/8 = 26 mm
12ft
perimeter of octagon is 128 cm= 8 * side side of the octagon=128/8=16 cm
The perimeter of an octagon that has one side of 2 inches is 16 inches.
8 (measure of each side) x 8 (total sides of an octagon) = 64cm
if there 8 sides on an octagon then 8 times 4 should give you your answer which is ....... 32