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A wire is first bent into the shape of a triangle Each side of the triangle is 20 inches long Then the wire is unbent and reshaped into a square What is the length of a side of the square?
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∙ 14y ago
wire is first bent into the shape of a triangle. Each side of the triangle is 16 cm long. Then the wire is unbent and reshaped into a rectangle. If the length of the rectangle is 17 cm, what is its width?
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Wiki User
∙ 14y ago15 inches.
20 x 3 = 60
60/4 = 15
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What is the length of a triangle with an area of 18 square inches and a height of 12 inches?
The length of a triangle with a height of 12 inches and an area of 18 square inches is 3 inches, since area is 1/2 * base * height. Therefore, 2 * area divided by height = 2 * 18 /12 = 3
A rectangle and triangle have equal areas - the rectangle's length is 12 inches and its width is 8 inches so if the base of the triangle is 32 inches what is the length in inches of the altitude drawn?
The rectangle has an area of 12 x 8 = 96 square inches. The triangle has an area of (1/2 * 32 * x). So, 16x = 96, therefore x = 6. The height of the triangle is 6 inches.
What is the leg length of an isosceles right triangle with a hypotenuse of 32 inches?
Each leg length is 16 times square root of 2 or about 22,627 inches to 3 decimal places
A wire is first bent into the shape of a rectangle with width and length Then the wire is unbent and reshaped into a square What is the length of a side of the square?
(width side of the rectangle + length side of the rectangle) divided by 2
A square and a triangle have equal areas and a side of the square is 10 inches and the base of the triangle is 10 inches then what is the height of the triangle?
Area triangle = 1/2 base x height Area square = length x width = 10in x 10in = 100sq in. Area triangle = area square Therefore: 1/2 x 10in x height = 100sq in height = 100 sq in x 2 / 10 in = 20 in
What is the length of a leg of an isosceles right triangle if it is area is 72 square inches?
What is the length of a leg of an isosceles right triangle if it is area is 72 square inches?
What is the length of a triangle with width 10 in. and area 72 in?
Length of triangle is 14.4 inches. Check: 0.5*14.4*10 = 72 square inches
What is the length of a side of an equilateral triangle with the area of 144 square inches?
The side length is 18.24 (18.23606) inches.
How can you find the area of a triangle in square inches?
-- Measure the length of the base, in inches. -- Measure the height of the triangle, in inches. -- Multiply the two numbers and take 1/2 of the product. 1/2 of the product is the area of the triangle, in square inches.
What is the length of a triangle with an area of 18 square inches and a height of 12 inches?
The length of a triangle with a height of 12 inches and an area of 18 square inches is 3 inches, since area is 1/2 * base * height. Therefore, 2 * area divided by height = 2 * 18 /12 = 3
What is the area of a triangle with side length of 15.5 inches?
A triangle with side a: 15.5, side b: 15.5, and side c: 15.5 inches has an area of 104.03 square inches.
What is the area of a regular triangle with side length of 15.5 inches?
A triangle with side a: 15.5, side b: 15.5, and side c: 15.5 inches has an area of 104.03 square inches.
What is the area of a right triangle with a base length of six inches and a height of six inches?
18 square inches
What is the length of the other leg when a right triangle has a hypotenuse of length 13 and a leg length is 7 inches smaller?
the square root of 133
The height of a triangle is four times the length of the base find the base and height of the triangle if the base is 18 square inches?
18 square inches is probably the area of the triangle, not the length of the base. The length of the base would be measured in inches (a unit of length), not square inches (a unit of area). So area = 1 / 2 * base * height = 18 square inches (given) height = 4 * base (given) 1 / 2 * base * 4 * base = 18 square inches 2 * base * base = 18 square inches base * base = 9 square inches base = 3 inches height = 4 * base = 4 * 3 inches = 12 inches Checking our work: height is 4 times the base (12 = 4 * 3) area is 18 (1/2 * 12 * 3).
A rectangle and triangle have equal areas - the rectangle's length is 12 inches and its width is 8 inches so if the base of the triangle is 32 inches what is the length in inches of the altitude drawn?
The rectangle has an area of 12 x 8 = 96 square inches. The triangle has an area of (1/2 * 32 * x). So, 16x = 96, therefore x = 6. The height of the triangle is 6 inches.
If a triangle has a height of 8 inches and an area of 120 sq inches what is the length of the base?
30 inches because 0.5*30*8 = 120 square inches
