A horizontal line has a slope of 0. If you're using the slope formula, then when the numerator is equal to 0 then the slope is 0.
Assuming that you mean that those are the (x,y) points, then solve this by using the formula for calculating slope. Chance in y / chance in x = slope so, (-5 - 0) / 0 - 0 Already you can see the problem. The denominator will equal 0, which means that it does not exist. The slope of that line does not exist, nor does the slope for any vertical line. On a completely separate note though, the slope of a horizontal line is 0.
The slope is zero.
The answer is 0.
y=12x+0 the slope is 12
A horizontal line has a slope of 0. If you're using the slope formula, then when the numerator is equal to 0 then the slope is 0.
If the original slope is 0, then the opposite reciprocal of 0 is still 0. Oops! Reciprocal of 0 (n/0) is undefined! A vertical line has undefined slope, the horizontal line has slope of 0.
if you define y = constant then the slope of any constant is 0 so if you define the line y = 0 the slope of 0 is 0.
The slope is undefined.
No slope is undefined i.e. a vertical line slope of 0 is a horizontal line... i believe...
y=mx has a slope of m, if the slope is 0, m must be 0. So the coefficient of x is 0.
Points: (-1, -1) and (0, 0) Slope: 1
Slope = (8 - 0)/(0 - 4) = -2
if the slope is 0, the line is horizontal.
Slope=0 Y-intercept=0
Assuming that you mean that those are the (x,y) points, then solve this by using the formula for calculating slope. Chance in y / chance in x = slope so, (-5 - 0) / 0 - 0 Already you can see the problem. The denominator will equal 0, which means that it does not exist. The slope of that line does not exist, nor does the slope for any vertical line. On a completely separate note though, the slope of a horizontal line is 0.
Because V in is the slope and when A is 0 slope is not 0 so v cant be 0