C=a/bd
If bd ≠ 0, then a/b + c/d (the common denominator is bd) = (a x d)/(b x d) + (c x b)/(d x b) = ad/bd + cb/db = ad/bd + cb/bd = (ad + cb)/ bd
5 units
16cm
A rational number is one that can be expressed as a/b The sum of two rational numbers is: a/b + c/d =ad/bd + bc/bd =(ad+bc)/bd =e/f which is rational The difference of two rational numbers is: a/b - c/d =ab/bd - bc/bd =(ab-bc)/bd =e/f which is rational The product of two rational numbers is: (a/b)(c/d) =ac/bd =e/f which is rational
If AC equals 6 and BD equals 4, then AB equals 5.
A = (1/2)(ac)(bd) = (1/2)(8)(9) = 36
ohh jeeeze!!!!!! lol
C=a/bd
0.82taka
ba=(16/(16+8))bd=(16/24)bd=(2/3)bd area of the rectangle = bd*bf area of triangle = (2/3)bd*bf/2=(1/3)*bd*bf 1/3
The hexadecimal number BD = 189 in base 10.
38.5
It is 16 units.
Draw a line from b perpendicular to the airstrip at point d. This will form two right triangles: abd and cbd. Using trigonometry, here is a solution: ad + dc = 1500 meters, ad = 1500 - dc tan 59o = bd/ad = 1.664, so bd = 1.664ad tan 34o = bd/dc = .674, so bd = .674dc bd = 1.664ad = 1.664(1500 - dc) bd = 2946 - 1.664dc .674dc = 2946 - 1.664dc so, dc = 1068 and, ad = 1500 - dc = 1500 - 1068 = 431 cos 59o = .515, cos 59o = ad/ab = 431/ab, .515ab = 431, so ab = 837 meters cos 34o = .829, cos 34o = dc/bc, .829bc = 1068, so bc = 1288 meters
9
If bd ≠ 0, then a/b + c/d (the common denominator is bd) = (a x d)/(b x d) + (c x b)/(d x b) = ad/bd + cb/db = ad/bd + cb/bd = (ad + cb)/ bd