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Can anyone solve for x log 4 X plus 16 plus log 4 X plus 4 equals 3?
log4(x) +16 +log4(x) +4=32log4(x)=-17log4(x)=-17/2x=4^(-17/2)=========================Since the parentheses have been lost from the question,it could easily be interpreted this way instead, (as well asa few others):x log(4x) + 16 + log(4x) + 4 = 3(x + 1) log(4x) = -174x = 10-17/(x+1)4x = the (x+1)th root of 10-17Come on back and solve that one for us.
What are the equivalent ratios for 2 to 8?
4:16
What are 2 equivalent fractions for 2 16?
2/16 = 1/8 = 4/32
What is the biggest 3 digit number that can be represented in hexidecimal notation?
Assuming your problem means 3 hexadecimal digits, we have the largest 3 digit number being "fff". Since f = 16 (base 10), we have that fff(base 16) = 16*16*16(base 10) = 4096 If it's a 3 digit decimal number, then 999, since hex can represent ANY number.
What are the equivalent ratios for 3 to 8?
3:8 is equivalent to 6:16 or 30:80 or 30000:80000
How do you solve log base16 8?
You divide log 8 / log 16. Calculate the logarithm in any base, but use the same base for both - for example, ln 8 / ln 16.
What is log base 4 of 16?
The logarithm base 4 of 16 is asking the question "4 raised to what power equals 16?" In this case, 4 squared is equal to 16, so the answer is 2. Therefore, log base 4 of 16 is equal to 2.
A logarithm is an exponent?
A logarithm is quite the opposite of an exponential function. Whereas an exponential is y=ax , a log is logay=x For example, log39=2 because you raise 3 by the 2nd power to get 9. In other words, log39=2 because 32=9 Logarithms are present because they are a handy way to solve exponential equations, and because calculators use them to great advantage.
What is logarithm in simple terms?
A logarithm is the inverse operation of exponentiation. It is used to find the power to which a fixed number (called the base) must be raised to produce a given number. Logarithms help simplify calculations involving very large or very small numbers.
How do you solve 16 as a power of 2?
In this case, trial and error is probably the easiest: 22 = 4, 23 = 8, 24 = 16 yes! A more genral answer is: the power that you want is log(16)/log(2) where the logarithm is calculated to any base (10 or e , or indeed any other).
Evaluate 81 to the power of log 16 with a base of 9?
It is 256.
What is the logarithm of 16 to the base 4?
There are two ways to solve this. One is using the definition of logarithms: solve the equation 4x = 16. This can be done by inspection, in this case. The other is to use a change-of-base, to change to a base your calculator can handle. For example, changing to base e: log416 = ln(16) / ln(4)
How do you solve the equation 5.2 log4 2x16?
Due to limitations with browsers mathematical operators (especially + =) get stripped from questions (leaving questions with not enough information to answer them) and it is not entirely clear what the log4 bit means. I guess that the log4 bit is logarithms to base 4 of 2x^16 (which I'll write as log_4(2x^16) for brevity). If this is so, use normal algebraic operations to make log_4(2x^16) the subject of the equation. With logs there are useful rules; given 2 numbers 'a' and 'b': log(ab) = log(a) + log(b) log(a^b) = b × log(a) Which means: log_4(2x^16) = log_4(2) + log_4(x^16) = log_4(2) + 16 × log(x) and the equation can be further rearranged: log_4(2x^16) = <whatever> → log_4(2) + 16 × log(x) = <whatever> → log(x) = (<whatever> - log_4(2)) / 16 Logarithms tell you the power to which the base of the logarithm must be raised to get its argument, for example when using common logs: lg 100 = 2 since 10 must be raised to the power 2 to get 100, ie 10² = 100. (lg is the abbreviation for logs to base 10; ln, or natural logs, is the abbreviation for logs to the base e.) With logs to base 4, it is 4 that is raised to the power of the log to get the original value. eg log_4(16) = 2 since 4^2 = 16. log_4(2) can be worked out: The log to any base of the base is 1 (since any number to the power 1 is itself). Now 2 × 2 = 2² = 4. → log_4(4) = 1 → log_4(2²) = 1 → 2 × log_4(2) = 1 → log_4(2) = ½ → log(x) = (<whatever> - ½) / 16 Back to the rearranged equation; with logs to base 4, if you make both sides the power of 4 you'll get: 4^(log_4(x)) = 4^(<whatever>) → x = 4^(<whatever>) which now solves for x.
How do you write a number as a power of 2?
For an exact power of 2 (1, 2, 4, 8, 16, 32, etc., but also 1/2, 1/4, etc.), you can try out different exponents until you get it right. To write any number (greater than 0) as a power of 2 is equivalent to taking the logarithm of that number in base 2, which is the same (if you call your number "n") as calculating log n / log 2 (using the same base for both logarithms - for example, both in base 10, or both in base e).
What is a logarithm?
log_a (b) [in words - log a of b], is like asking - what power of a equals b. For example: log_10 (100) = 2 because 10^2 = 100 log_2 (16) = 4 because 2^4 = 16
What is the hexadecimal equivalent of the decimal number 1016?
1016 in base 10 = 3F8 in base 16.
What is 9 to the power of 16?
The answer sought can be approximated by using logarithms. The logarithm of 916 = 16 X log (9) = 15.26788015. The integral part of this number is the power of 10 in the answer, and the other part of the answer is the antilog of 0.26788015 or 1.853020184. Therefore, 1.853020184 x 1015 is the answer, to the largest number of digits on my calculator, assuming that the 9 and 16 are taken as exact.
