3ab + 3ac + 2b2 + 2bc = 3a(b + c) + 2b(b + c) = (3a + 2b)(b + c)
(a+b)3=a3+b3+3ab(a+b) a3+b3=(a+b)3-3ab(a+b) a3+b3=(a+b)(a2-ab+b2)
(a+b)cube = a cube + b cube + 3a square b + 3ab square
5ab-2ab+4a-b+5b = 3ab+4a+4b
(a + b)(b + c)
3ab - a - 3b2 + b = -3b2 + 3ab + b - a = -3b(b - a) + 1(b - a) = (1 - 3b)(b - a)
(3b - 1)(a - b)
(a+b)(3b+1)
3ab + 3ac + 2b2 + 2bc = 3a(b + c) + 2b(b + c) = (3a + 2b)(b + c)
6
3a(b+c)+2b(b+c)
(3a - 2c)(b - d)
3 times a times a times b
Factorizing 3ab + 3ac gives 3a (b + c).Factorizing is to express a number or expression as a product of factors.When factorizing always look for common factors. To factorize (3ab + 3ac) look for the highest factor between the two terms (3a). 3ab + 3ac = 3a (b + c)
(a+b)3=a3+b3+3ab(a+b) a3+b3=(a+b)3-3ab(a+b) a3+b3=(a+b)(a2-ab+b2)
It is an algebraic expression because it has no equality sign.
(a+b)cube = a cube + b cube + 3a square b + 3ab square