2y
When you see "y times 2," it means you are multiplying the variable y by the number 2. So the expression "y times 2" can be written as 2y. This is a simple algebraic expression where the coefficient of y is 2.
1.5
(y - 8)(y - 2)
If 2y = 2628, 2628/2 = 1314, Therefore y = 1314.
5
if you take a factor of (Y) you end up with Y(X+5Z-2).
2(x+y) To find the answer above, look at the question (2x + 2y), and see what the common factors are. In this case, it is "2", which is present in both "x" and "y". Put the "2" on the outside, and write the rest of the equation.
(2y + 1) + (y^2 + 1) = 2y + 1 + y^2 + 1 = y^2 + 2y + 2
2y
x2 - 4y2 = 16∴ (x - 2y)(x + 2y) = 162y - x = 2∴ x = 2y - 2∴ ([2y - 2] - 2y)([2y - 2] + 2y) = 16∴ (y - 1 - y)(y - 1 + y) = 16∴ -1(2y - 1) = 16∴ 1 - 2y = 16∴ -2y = 15∴ y = -7.52y - x = -2∴ -15 - x = -2∴ x = -13So the point of intersection is (-13, -7.5)
2x2 + 2y - 8 = 0 2(x2 + y - 4) = 0 and other than removing the two outside the bracket, this cannot be factorised further, nor simplified.
(4x)(2y) would be factored as such: 4x = 2 • 2 • x 2y = 2 • y 2(2x)(y)
When you see "y times 2," it means you are multiplying the variable y by the number 2. So the expression "y times 2" can be written as 2y. This is a simple algebraic expression where the coefficient of y is 2.
3xy-2y=0 3xy=2y y=2y (3x) y/2y=3x 1/2=3x multiply across by 2 1=6x 1/6=x therefore substituting x=1/6 into 3xy-2y; 3(1/6)y-2y=0 1/2y=2y y=2y/0.5 0.5 aka 1/2 y=1
(A) 3x + 2y = -2 (B) 6x - y = 6 (A) + 2(B): 3x + 2y + 12x - 2y = -2 + 12 or 15x = 10 or x = 2/3 substitute this value of x in (A) 2 + 2y = -2 2y = -4 and y = -2 Answer: x = 2/3, y = -2
Y squared (Y^2)