You get the answer by doing 5 times 3.7 on a calculator and you get 18.5 so the answer is 18.5 square inches.
To find the area of a rectangle, multiply the length times the width.
(4.8 x 7.5) = 36 square inches
Let the width of the rectangle be represented by "w" inches. Since the length is twice the width, it can be expressed as "2w" inches. The formula for the perimeter of a rectangle is P = 2(l + w), where P is the perimeter, l is the length, and w is the width. Substituting the given values into the formula, we get 48 = 2(2w + w). Simplifying, we find that 48 = 6w. Solving for w, we find that the width of the rectangle is 8 inches, and the length is 16 inches.
To find the area of a rectangle, multiply the length by the width. 3 x 5 = 15. Do not forget to include the units, however - if the units of the rectangle are in inches, then the answer to the question will be 15 inches squared (15 in2).
Depends on the shape of the area. For a rectangle the answer is the width * the height, assuming both measurements are in inches.
To find the area of a rectangle, multiply the length times the width.
To find the area of a rectangle, multiply the length times the width. The result will be in square inches.
A rectangle 6.3 inches long and 12.2 inches high has an area of 76.86 inches.
Length of rectangle is 5 inches and its width is 4 inches Check: 2*(5+4) = 18 inches which is its perimeter
The perimeter of a rectangle = 2 x (length + width) = 2 x (12 + 8) = 2 x 20 = 40 inches
7
10 in. A+LS
36 square inches is the area.
To find the area of the rectangle, multiply the length times the width: 1.24 x .67 = .8308 square inches.
To find the area of a rectangle, you multiply its length by its width. For an 11x13 rectangle, the area is calculated as (11 \times 13 = 143) square inches. Therefore, the area of an 11x13 rectangle is 143 square inches.
Using Pythagoras' theorem it is about 10.81665383 inches.
The dimensions are: length = 15 inches and width = 7 inches Check: 15*7 = 105 square inches