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10698 ÷ gcf = n remainder 18 → gcf divides 10698 - 18 = 10680

6443 ÷ gcf = m remainder 35 → gcf divides 6443 - 35 = 6408

14995 ÷ gcf = k remainder 43 → gcf divides 14995 - 43 = 14952

Therefore want gcf(10680, 6408, 14952) = 2136.

Using prime factorization method:

10680 = 2³ x 3 x 5 x 89

6408 = 2³ x 3² x 89

14952 = 2³ x 3 x 7 x 89

hcf = 2³ x 3 x 89 = 2136

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Q: The greatest number which divides 10698 6443 14995 leaving 18 35 43 as remainder respectively?
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