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y=3x^2-4x=3
y=3x^2-4x-3
y = ax^2 + bx + c is the parabola
y = 3x^2-4x-3
x-coordinate of vertex is -b/2a
= -(-4) / (2)(3)
= +4 / (2)(3) = 4/6=2/3
y coordinate of the vertex:
y = ax^2+bx+c
y = 3(2/3)^2-4(2/3)-3
y= 3(4/9) -8/3 -3
y=12/9-8/3-3 = -13/3
Vertex : ( 2/3, , -13/3 )
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