Find the vertex of y equals 3x2-4x equals 3?

Answer 1

y=3x^2-4x=3

y=3x^2-4x-3

y = ax^2 + bx + c is the parabola

y = 3x^2-4x-3

x-coordinate of vertex is -b/2a

= -(-4) / (2)(3)

= +4 / (2)(3) = 4/6=2/3

y coordinate of the vertex:

y = ax^2+bx+c

y = 3(2/3)^2-4(2/3)-3

y= 3(4/9) -8/3 -3

y=12/9-8/3-3 = -13/3

Vertex : ( 2/3, , -13/3 )