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Find three consecutive integers such that the square of the first added to the last is 8?
Wiki User
∙ 14y ago
The integers are: x, x+1, and x+2.
x2 + (x+2) = 8
x2 + x - 6 = 0
(x - 2) (x + 3) = 0
x = + 2
x = - 3
Two solutions:
=> The integers are 2, 3, and 4
=> The integers are -3, -2, and -1
Wiki User
∙ 14y ago
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