Let the first integer be x, the second be x + 1, and the third be x + 2. So we have:
2x + 4(x + 1) = 2(x + 2) + 20
2x + 4x + 4 = 2x + 4 + 20
4x = 20
x = 5
x + 1 = 6
x + 2 = 7
Thus these numbers are 5, 6, and 7
Check.
10-11-12
If the first of these consecutive integers is x, the second integer would be x + 1, and the third integer would be x + 2.Since the sum of the second and the third integer is 17, we can writex + 1 + x + 2 = 172x + 3 = 172x + 3 - 3 = 17 - 32x = 142x/2 = 14/2x = 7Thus, the consecutive integers are 7, 8, and 9.
Let the first consecutive integer be x. So that:the second integer is x + 1,the third integer is x + 2, andthe fourth integer is x + 3.We have:(x + 1) + (x + 3) = 1322x + 4 = 1322x = 128x = 64 the first integerThus, the four consecutive integers are 64, 65, 66, and 67.
The sum of the first 60 positive integers (1 + 2 + 3 + .... + 59 + 60) is equal to 1830.
This doesn't work for integers. Using 7, 8 and 9 comes up with 146 which is the closest you can get.
No, it is not possible.
24. The second is 26.
Consecutive integers could be thought of as counting numbers in a row. One of them is "lowest" and the next one will be one more than that, and the last one will be one more than the second one. The numbers 7, 8 and 9 and 46, 47 and 48 are each said to be three consecutive integers. You often come across a question that tells you that 3 consecutive integers add up to a value. Example 3 consecutive integers add to 6. What are the integers? Let the first integer be x the second is then x +1 the third x+2 add them x+x+1+x+2 =3x+3 and this would be equal to 6. we then have the equation 3x+3=6 3x=3 x=1 so the first integer is 1, the second would be 2 and the third 3
Consecutive means one after another.If the first is a, then the second is a+1.The sum of these isa + a + 1 = 2a+1 = -3772a = -378a = -189So the two numbers are -189 and -188
The sum of the first four non-negative, consecutive, even integers is 20.
10-11-12
-7
2, 3, 4 and 5.
The first integer is 17.
I assume you mean what are the two consecutive integers. Algebraically; X = integers.X + (X + 1) = 2752X + 1 = 2752X = 274X = 137============solution setorSince the consecutive integers differ by 1, then the first number is 274/2 = 137, so the second one is 1 more, 138.
18, 20 and 22
If the first of these consecutive integers is x, the second integer would be x + 1, and the third integer would be x + 2.Since the sum of the second and the third integer is 17, we can writex + 1 + x + 2 = 172x + 3 = 172x + 3 - 3 = 17 - 32x = 142x/2 = 14/2x = 7Thus, the consecutive integers are 7, 8, and 9.