Find an equation of variation where y varies directly as x. One pair of values is y = 80 when x = 40
If the points have both positive y-values and x-values it is quadrant 1 If the points have a negative x-value and a positive y-value it is quadrant 2 If the points have both negative y-values and x-values it is quadrant 3 If the points have a positive x-values and a negative y-value it is quadrant 4
y = x This is a line and a function. Function values are y values.
depends on what the problem is
Given a value for the variable x, you find (calculate) the corresponding value of y. These (x, y) pairs are part of the table. You cannot complete the table because there are infinitely many possible values of x.
The answer depends on the values of x and y. The answer depends on the values of x and y. The answer depends on the values of x and y. The answer depends on the values of x and y.
well u have to find out the values of x and y first to answer it! =)
Find an equation of variation where y varies directly as x. One pair of values is y = 80 when x = 40
you find the first point
plug in 0 to x and y values P.S. you spelt Intercepts wrong
An abstract equation is an equation where it is impossible, with the information given, to find the numeric values of the variables. For example 2X=4Y can be reduced to X=2Y or Y=X/2 or 2=X/Y but you cannot find the numeric values of X or Y.
If the points have both positive y-values and x-values it is quadrant 1 If the points have a negative x-value and a positive y-value it is quadrant 2 If the points have both negative y-values and x-values it is quadrant 3 If the points have a positive x-values and a negative y-value it is quadrant 4
pretend they = y factor to find x intercepts if they exist, sub 0 for x and find the y-intercept pick a few extra x values, calculate y-values to get a table of values. plot the points from the table. Draw a curve thru the points.
You can graph the line and read out from the graph where the line intersects the X and Y axes. You can input values for Y until you find one that gives an X = 0 and input X values until you find one that gives a Y = 0 (This is the same as setting either X equal to zero and solving the equation the setting Y = 0 and solving)
to find the y-intercept you plug in your x and y values in to the equation of y=mx+b. b is the y intercept and m is the slope. To find the x-intercept, set y = 0, and find value of x that satisfies the equation. If it is a line in the form y=mx+b, then the x-intercept will be at x= -b/m
use y = g(x) make a table of y values for several x values Find max/min values using derivative. graph the ordered pairs.
2x + 4y = 72x - 2x + 4y = 7 - 2x4y = -2x + 74y/4 = -2x/4 + 7/4y = -(1/2)x + 7/4Now that y is a function of x, you can give some values for x and find the corresponding values for y. (There are infinitely values for x an y)