The answer is 20.you get this answer by reading the instructions.
x2+x-6=x2+3x-2x-6x2+x-6=x(x+3)-2(x-3)x2+x-6=(x+3)(x-2)
x2 + x + 1 = 0 ∴ x2 + x + 1/4 = -3/4 ∴ (x + 1/2)2 = -3/4 ∴ x + 1/2 = ± √(-3/4) ∴ x = - 1/2 ± (i√3) / 2 ∴ x = (-1 ± i√3) / 2
-2
(X^2 - 1)/(x-1) = (X+1)(X-1)/(X-1) = X+1
it depends on what x2 and x are. so an example is 32 -3=3 cause 3 times 2 =6
x2+x-6=x2+3x-2x-6x2+x-6=x(x+3)-2(x-3)x2+x-6=(x+3)(x-2)
It is y^3/x^2
x(x + 2)
Assuming simplify = factor...x3 - 3x + 2 = (x-1)(x2+x-2)
f'(x) = (x2 - x)1/21. Add one to the exponent2. Divide step 1 by the exponent plus one= (x2 - x)1/2+1____________1/2 + 1= (x2 - x)3/2_________ 3/2= (2/3) (x2 - x)3/2 + CIt may also be written:[2(x2 - x)3/2 / 3] + CCheck:f(x) = (2/3) (x2 - x)3/2Using the chain rule:f'(x) = (2/3) (3/2) (x2 - x)3/2-1= (x2 - x)1/2
(x2 - x - 20) / (x2 + 8x + 16) = [(x - 5)(x + 4)] / (x + 4)2 = (x - 5) / (x + 4)
x4 - x2 - 12 = (x2 + 3) (x2 - 4)And (x2 - 4) = (x + 2) (x - 2)So the original expression = (x2+ 3) (x + 2) (x - 2)
To simplify the equation:(x2 - x - 12) / [(x2 - 9) / (x2 - 3x)]first, factor the numerator:= (x + 3)(x - 4) / [(x2 - 9) / (x2 - 3x)]Now bring the bottom term, (x2 - 3x), up to the top (remember, a/(b/c) = ac/b):= (x + 3)(x - 4)(x2 - 3x) / (x2 - 9)then factor the extra "x" out of the term (x2 - 3x):= (x + 3)(x + 4)(x - 3)x / (x2 - 9)now note that the bottom term is a difference of squares, and factor that out:= (x + 3)(x + 4)(x - 3)x / (x + 3)(x - 3)now you can see that the two terms on the bottom can be factored out of the top term, giving you:x(x + 4)which equals:x2 + 4x
-x2 = x - 6 x2 + x - 6 = 0 (x - 2)(x + 3) = 0 x ∈ {-3, 2}
To simplify x3-9x, you factor out the x, leaving you with x(x2-9). You can then take the square root of both numbers and end up with x(x+3)(x-3).
(3x - 3)(x/6)(x2 - x)= (3)(x - 1)(x/6)(x)(x - 1) = (1/2)(x2)(x -1)2 = (1/2)(x2)(x2 - 2x + 1) = (1/2)x4 - x3 + (1/2)x2
Factor it out: (x+2) squared