3(x - 8)
8x2-3x-5 = (8x+5)(x-1) when factored
(x2 + 3x + 5)(x2 - 3x + 4)
3x + 24 = 3(x + 8)
The factors are -1(2x + 1)(3x + 4)
6(x - 4)
It is: (2x+3)(3x-8) when factored
3x squared minus 25x minus 28
(x-3)(3x+1)
(3x + 1)(x - 5)
x(3x - 2)
(18x^(2) - 3x) '3x' is a common factor to both terms , so 'take it out'. Hence 3x(6x - 1) Fully factored.
3x2 -14x -24 can be factored as (3x + 4)(x - 6).
3x^(2) +9x - 2x -6 Collect 'like terms'. Hence 3x^(2) + 7x - 6 Next write down all the factors of '3' and '6' Hence 3 ; 1' & 3' 6 ; 1,6 ; 2,3. From these pairs of number we select a pair from each coefficient, that add/multiply to '7' . Hence (3' x 3 ) & (1' x 2) ; NB 'dashes' (') to indicate source of numbers. Write up brackets (3x 2)(x 3) -2)(x + 3) Next we notice that the '6' is negative, so the two signs are different (+/-) The '7x' is positive , so the larger number takes the positive sign . Hence (3x - 2)(x + 3)
(3x + 8)(3x - 8)
3x(x^2 - 5)
3x2-x-2 = (3x+2)(x-1)
x2-3x-10 = (x+2)(x-5) when factored