4
roughly
4 pieces of A4 fit on one piece of A2.
( a2 ) ( a2+1 )
A4*2 = A3 A3*2 = A2 = 2*2*A4 A2*2 = A1 = 2*2*2*A4 = 8*A4 Answer: 8 pieces of A4 zized papers will fit on 1 sheet of A1.
Here a1 = -6, a2 = -1, a3 = 4 & a4 = 9 d = a2-a1 = -1-(-6) = -1+6 = 5 d = a3-a2 = 4-(-1) = 4+1 = 5 d = a4-a3 = 9-4 = 5 Therefore the common difference d = 5
An A4 page is too large to fit into an A5 page, as A4 is twice as large than A5. An A5 page would fit into an A4 page twice.
an a2 has 6 pieces of a4
4 pieces of A4 fit on one piece of A2.
While there are many ways of doing it, the simplest way is to use the SUM function and a range in it like this: =SUM(A1:A5)
Excel formulas that will find the average of cells A1, A2, and A4 are: =AVERAGE(A1 ,A2, A4) or =AVERAGE(A1:A2, A4)
( a2 ) ( a2+1 )
A4*2 = A3 A3*2 = A2 = 2*2*A4 A2*2 = A1 = 2*2*2*A4 = 8*A4 Answer: 8 pieces of A4 zized papers will fit on 1 sheet of A1.
At most n-1. However, it can be a lot fewer. For example, calculating A10 does not require 9 multiplications. A*A = A2 A2*A2 = A4 A4*A4 = A8 A8*A2 = A10 Only 4 multiplications were required.
A2 is the biggest then A4 then A1
If you mean a2 x a2... the answer is a4
(a2+2b2-2ab)(a2+2b2+2ab)
Of course you can square a square, because a square is a square isn't it. A2 * A2 = A(²⁺²) = A4
I believe A2 times A2=A4 (A to the power of 4).