4 pieces of A4 fit on one piece of A2.
A4*2 = A3 A3*2 = A2 = 2*2*A4 A2*2 = A1 = 2*2*2*A4 = 8*A4 Answer: 8 pieces of A4 zized papers will fit on 1 sheet of A1.
( a2 ) ( a2+1 )
Here a1 = -6, a2 = -1, a3 = 4 & a4 = 9 d = a2-a1 = -1-(-6) = -1+6 = 5 d = a3-a2 = 4-(-1) = 4+1 = 5 d = a4-a3 = 9-4 = 5 Therefore the common difference d = 5
An A4 page is too large to fit into an A5 page, as A4 is twice as large than A5. An A5 page would fit into an A4 page twice.
4 pieces of A4 fit on one piece of A2.
an a2 has 6 pieces of a4
While there are many ways of doing it, the simplest way is to use the SUM function and a range in it like this: =SUM(A1:A5)
Excel formulas that will find the average of cells A1, A2, and A4 are: =AVERAGE(A1 ,A2, A4) or =AVERAGE(A1:A2, A4)
A4*2 = A3 A3*2 = A2 = 2*2*A4 A2*2 = A1 = 2*2*2*A4 = 8*A4 Answer: 8 pieces of A4 zized papers will fit on 1 sheet of A1.
( a2 ) ( a2+1 )
At most n-1. However, it can be a lot fewer. For example, calculating A10 does not require 9 multiplications. A*A = A2 A2*A2 = A4 A4*A4 = A8 A8*A2 = A10 Only 4 multiplications were required.
A2 is the biggest then A4 then A1
(a2+2b2-2ab)(a2+2b2+2ab)
If you mean a2 x a2... the answer is a4
Of course you can square a square, because a square is a square isn't it. A2 * A2 = A(²⁺²) = A4
I believe A2 times A2=A4 (A to the power of 4).