Well, honey, looks like we've got ourselves an arithmetic sequence here with a common difference of 7. So, to find the nth term, we use the formula a_n = a_1 + (n-1)d. Plug in the values a_1 = 12, d = 7, and n to get the nth term. Math doesn't have to be a drag, darling!
Expressed in terms of n, the nth term is equal to 7n - 2.
The nth term in this arithmetic sequence is an=26+(n-1)(-8).
46n9
Tn = 10 + n2
[ 6n + 8 ] is.
It is: nth term = 7n-9
Expressed in terms of n, the nth term is equal to 7n - 2.
The nth term in this arithmetic sequence is an=26+(n-1)(-8).
It is: nth term = 35-9n
46n9
Tn = 10 + n2
[ 6n + 8 ] is.
It is: 26-6n
Well, isn't that just a lovely pattern we have here? Each term is increasing by 4, isn't that delightful? So, if we want to find the nth term, we can use the formula: nth term = first term + (n-1) * common difference. Just like painting a happy little tree, we can plug in the values and find the nth term with ease.
The common difference (d) between successive terms is -9. The first term (a) is 26 The formula for the nth term [a(n)] of an Arithmetic Series is , a + (n - 1)d. Inputting the values for a and d gives :- a(n) = 26 - 9(n - 1) = 26 - 9n + 9 = 35 - 9n......where n = 1,2,3......
t(n) = 4n2 - 4n + 2
The sequence 20, 14, 8, 2 decreases by successive differences of 6, 6, and 6, indicating a consistent pattern. This means the sequence follows a linear pattern with a common difference of -6. The nth term can be expressed as ( a_n = 20 - 6(n-1) ), simplifying to ( a_n = 26 - 6n ). Thus, the nth term of the sequence is ( 26 - 6n ).