Yes, you can make 11 using only four 2s by using the following mathematical expression: (2 + 2) x (2 + 2) = 4 x 4 = 16. Then, subtract (2/2) to get 16 - 1 = 15. Finally, take the square root of 15 to get √15 ≈ 3.87, which is close to 4. Therefore, using four 2s, you can approximate 11 by following these steps.
(2x2x2)/2 + 2
2s + 16 = 4s - 6 Subtract 2s from both sides: 16 = 2s - 6 Add 6 to both sides: 22 = 2s divide both sides by 2: s = 11
Yes
42 can be divided by 2 once. The result, 21, is not divisible by 2.
Yes, you can make 11 using only four 2s by using the following mathematical expression: (2 + 2) x (2 + 2) = 4 x 4 = 16. Then, subtract (2/2) to get 16 - 1 = 15. Finally, take the square root of 15 to get √15 ≈ 3.87, which is close to 4. Therefore, using four 2s, you can approximate 11 by following these steps.
If p = 2s + 5, then s = (p-5)/2 or 1/2 (p-5) --- p = 2s +5 p-5 = 2s (p-5)/2 = s
If 2s = 5 then s = 2.5. So by letting s equal 2.5 (two and one half) you will allow 2s to equal 5.
7-2s+4+5s ..... Okay first you combine like terms(add the like terms)..so its going to be 11+3s I did 7+4=11 then -2s+5s=3s So the answer can be 11+3s or 3s+11
4s2 - 9 can be expressed by using the identity: a2 - b2 = (a-b)(a+b) Therefore, 4s2 - 9 = (2s)2 - 32 = (2s-3)(2s+3)
2r + 2s = 50 2r - s = 17 therefore 4r - 2s = 34 Add so that you can eliminate one of the variables: 2r + 2s = 50 4r - 2s = 34 ---------------- 6r + 0s = 84 Solve for r: 6r = 84 r = 14 Substitute r into one of the original equations: 2(14) + 2s = 50 28 + 2s = 50 2s = 22 s = 11 Doublecheck with the other original equation: 2(14) - 11 = 28 - 11 = 17
no.
(2x2x2)/2 + 2
2s + 16 = 4s - 6 Subtract 2s from both sides: 16 = 2s - 6 Add 6 to both sides: 22 = 2s divide both sides by 2: s = 11
2s(-s^3 + 2s^2 - 5) -2s(s^3 - 2s^2 + 5)
square root of 0.2^-2=5
Yes