4 feet high by 8 feet wide = diagonal of 107.28 inches.
To find the diagonal of a rectangle, you can use the Pythagorean theorem. The diagonal (d) can be calculated using the formula (d = \sqrt{(length^2 + width^2)}). For a rectangle that is 46 feet by 66 feet, the diagonal is (d = \sqrt{(46^2 + 66^2)} = \sqrt{(2116 + 4356)} = \sqrt{6472} \approx 80.5) feet. Therefore, the diagonal is approximately 80.5 feet long.
length of diagonal of 20 of a 20 feet and 15 width.
The diagonal is 48.877 feet.
Using Pythagoras' theorem the length of the diagonal is 20 feet
Diagonal = 36.9 feet
The diagonal is 45.61 feet.
The diagonal is 69.856 feet.
The diagonal measurement for 36 feet by 36 feet is 50.91 feet.
The diagonal is 25 feet.
The diagonal is approximately 38.42 feet.
4 feet high by 8 feet wide = diagonal of 107.28 inches.
The length of a rectangle that has a diagonal of 25 feet and a width of 15 feet is 20 feet.
The length of the diagonal is about 16.03 feet.
The diagonal is 14.142 feet.
Using Pythagoras: 322+362 = 2320 and the square root of this is the length of the diagonal
To find the diagonal of a rectangle, you can use the Pythagorean theorem. The diagonal (d) can be calculated using the formula (d = \sqrt{(length^2 + width^2)}). For a rectangle that is 46 feet by 66 feet, the diagonal is (d = \sqrt{(46^2 + 66^2)} = \sqrt{(2116 + 4356)} = \sqrt{6472} \approx 80.5) feet. Therefore, the diagonal is approximately 80.5 feet long.