4 feet high by 8 feet wide = diagonal of 107.28 inches.
To find the diagonal of a rectangle, you can use the Pythagorean theorem. The diagonal (d) can be calculated using the formula (d = \sqrt{(length^2 + width^2)}). For a rectangle that is 46 feet by 66 feet, the diagonal is (d = \sqrt{(46^2 + 66^2)} = \sqrt{(2116 + 4356)} = \sqrt{6472} \approx 80.5) feet. Therefore, the diagonal is approximately 80.5 feet long.
length of diagonal of 20 of a 20 feet and 15 width.
The diagonal is 48.877 feet.
Using Pythagoras' theorem the length of the diagonal is 20 feet
The diagonal is 45.61 feet.
Diagonal = 36.9 feet
The diagonal is 69.856 feet.
The diagonal measurement for 36 feet by 36 feet is 50.91 feet.
The diagonal is 25 feet.
The diagonal is approximately 38.42 feet.
4 feet high by 8 feet wide = diagonal of 107.28 inches.
The length of a rectangle that has a diagonal of 25 feet and a width of 15 feet is 20 feet.
The length of the diagonal is about 16.03 feet.
The diagonal is 14.142 feet.
Using Pythagoras: 322+362 = 2320 and the square root of this is the length of the diagonal
To find the diagonal of a rectangle, you can use the Pythagorean theorem. The diagonal (d) can be calculated using the formula (d = \sqrt{(length^2 + width^2)}). For a rectangle that is 46 feet by 66 feet, the diagonal is (d = \sqrt{(46^2 + 66^2)} = \sqrt{(2116 + 4356)} = \sqrt{6472} \approx 80.5) feet. Therefore, the diagonal is approximately 80.5 feet long.