2a+6b
(ab/b) / (4a/5b) =(ab / b) * (5b / 4a) = (5ab2 / 4ab)= 5 / (4b)
5ab-2ab+4a-b+5b = 3ab+4a+4b
Add the equations: 4a + 4a - 5b + 5b = 7 + 17 ie 8a = 24 a = 3, so b = 1
The expression is: (4a+b)/(2a-5b)
2a+6b
3a - 2b
4a - 5b = 74a +5b = 17From the first equation:4a = 7 + 5bsubstitute this value in the second equation:7 + 5b + 5b = 177 + 10b = 1710b = 10b = 1Now,solve for a :4a - 5(1) = 74a = 7 + 54a = 12a = 3
(ab/b) / (4a/5b) =(ab / b) * (5b / 4a) = (5ab2 / 4ab)= 5 / (4b)
5ab-2ab+4a-b+5b = 3ab+4a+4b
Add the equations: 4a + 4a - 5b + 5b = 7 + 17 ie 8a = 24 a = 3, so b = 1
The expression is: (4a+b)/(2a-5b)
6c-4c =2c
These days, lots of secondary schools in England are starting to settle for a level 4a. The truth is, I am in a school that specialises in business and enterprise and in some cases, a level 5b at the end of year 7 may place you in top set for year 8. I achieved a level 6c at the end of year 7 and ended up in top set for year 8. Really, a 4a, 5c or 5b is average; occasionally a 5b may be high.
i dont really know
3a - 2b
Simultaneous Equations 4a - 5b = 7 4a + 5b = 17 Add the two , this will eliminate 'b' 8a = 24 Divide both sides by '8' a = 3 When a= 3 , substitute into eityher equation for 'b'. 4(3) + 5b = 17 12 + 5b = 17 5b = 17 - 12 = 5 5b = Divide both sides by '5'. Hence 'b = 1'.