2 3/4 ÷ 1/4 = (2×4+3)/4 ÷ 1/4 = 11/4 ÷ 1/4 = 11/4 × 4/1 = (11×4)/(4×1) = 44/4 = 11
11/3 1 ÷ 3/4 = 1 x 4/3 = 4/3 = 11/3
18. 1+3=4 3+4=7 4+7=11 7+11=18
4/3 or 11/34/3 or 11/34/3 or 11/34/3 or 11/3
It is: 11/12 -3/4 = 1/6
-(4-3) -(1) -1
a = 4
4 - 5X = 1 + 6Xadd 5X to each side4 = 1 + 11Xsubtract 1 from each side3 = 11Xdivide each sides integers by 113/11 = X=========check in original equation4 - 5(3/11) = 1 + 6(3/11)4 - 15/11 = 1 + 18/11( now 4 = 44/11 and 1 = 11/11 )44/11 - 15/11 = 11/11 + 18/1129/11 = 29/11=============checks
2 3/4 ÷ 1/4 = (2×4+3)/4 ÷ 1/4 = 11/4 ÷ 1/4 = 11/4 × 4/1 = (11×4)/(4×1) = 44/4 = 11
3^(-4) = (1/3)^4 = 1/81
11/3 1 ÷ 3/4 = 1 x 4/3 = 4/3 = 11/3
well that depends is it (-11,-10) and (-1,-4) or is it (-1,-11) (-4,-10) either way I'll solve the slope for both. so the first way with (-11,-10) (-1,-4) is to subtract the two y's over the two x's so -10--4/-11--1 which equals -10+4/-11+1 which equals -6/-10 and when you reduce you get 3/5 then the second ex. would be -4--11/-1--10 = -4+11/-1+10 = 6/9 reduce to 2/3.
| 2x + 3 | = 11 make 2 cases case 1) 2x + 3 = 11; solve x = 4 case 2) 2x + 3 = -11; solve x = -7 always 2 cases one = positive and one = negative
2/3 +4/6 =
3/11 = 12/44 1/4 = 11/44 3/11 is bigger.
2x - 3y = 4 x + 4y = 3 Write the augmented matrix: 2 -3 4 1 4 3 Multiply the first row by 1/2: 1 -3/2 2 1 4 3 Subtract the second row from the first row: 1 - 3/2 2 0 -11/2 -1 Multiply the second row by -2/11: 1 -3/2 2 0 1 2/11 Multiply the second row by 3/2 and add it to the first row: 1 0 25/11 0 1 2/11 Thus x = 25/11 and y = 2/11 Check:
(5 + 4 - 3 - 2) x 1 = 4