y - 2 = 5 is the same as y = 7, which is a horizontal line above the x-axis at y=7.
Straight lines.
y-intercept is -2, so start at the point (0,-2) slope is 1 so move up 1 and over 1. use a straight edge to connect the dots and continue the line.
1
(y^2 - 4) / (y + 2) = [(y -2)(y+2)]/(y+2) = y-2
A "y" with two dots above it, known as "ÿ," is called a diaeresis or umlaut. In languages like French and German, it can indicate that the vowel is pronounced separately from the preceding vowel, affecting the word's pronunciation. In some contexts, it can also appear in transliterations or specific names.
It isn't supposed to have dots. Usually dots on coins are made by nicks in the die.
above are examples. You need a y and x axis (labelled), data (dots) and the data joined up by a line. Like a scatter graph but with the dots joined up
y - 2 = 5 is the same as y = 7, which is a horizontal line above the x-axis at y=7.
y + x = -2 x = -y - 2Plug in numbers for y and solve for x. Then graph the x's and y's, and connect the dots. The x direction is right tot left. The y direction is up and down. So if y = -1, then x = -1. If y = 1 then x=-3.
Y = 2 The graph is a horizontal line passing through the point Y=2 on the Y=axis. The line is parallel to the X-axis, and exactly 2 units above it everywhere.
Straight lines.
y-intercept is -2, so start at the point (0,-2) slope is 1 so move up 1 and over 1. use a straight edge to connect the dots and continue the line.
Any two numbers of this type can be solved using boolean logics....... It is very simple once had a glance on it . Here is a method to prove x=y where x and y are any numbers..... let XY = XY We can rewrite the above as ð X2 - (X+Y)*X = Y2 - (X+Y)*Y ð Multiplying both sides with 2/2 we get ð X2 - 2*x*(X+Y)/2 = Y2 - 2*Y*(X+Y)/2 ð Adding (X+Y)2/2 on both sides we get ð X2 - 2*x*(X+Y)/2 + (X+Y)2/2= Y2 - 2*Y*(X+Y)/2 + (X+Y)2/2 ð This is in the form of a2-2ab +b2 = (a+b)2 ð (X - (X+Y)/2)2 = (Y-(X+Y)/2)2 ð Canceling the squares on both sides(case condition) ð X-(X+Y)/2 = Y - (X+Y)/2 ð Canceling (X+Y)/2 on both sides ð X=Y
Draw a blank graph (x-y axis), then start plotting points until you find the straight-line (e.g. plot at least 2 points, then get a straight-edge and connect the dots):(x,y)(0,0)(1,-2)(2,-4)(-1,2)(-2,4)
(x - y)2 - z2 is a difference of two squares (DOTS), those of (x-y) and z. So the factorisation is [(x - y) + z]*[(x - y) - z] = (x - y + z)*(x - y - z)
Positive x- and y-coordinates of a point in the first quadrant.