5x + 3y = -6
3x - 2y = 4 (multiply by 2 the first equation, multiply by 3 the second equation)
10x + 6y = -12
9x - 6y = 12 (add both the equations)
19x = 0 (divide by 19 both sides)
x = 0 (substitute 0 for x into the first equation)
5x + 3y = -6
5(0) + 3y = -6
3y = -6 (divide by 3 to both sides)
y = -2
Thus, (0, -2) is the solution of the given system of the equations.
Add the equations: 4a + 4a - 5b + 5b = 7 + 17 ie 8a = 24 a = 3, so b = 1
True
8840-026
Two equations, two unknownsFirst, multiply 3a + 2b = 70 by 4. This gives the equation 12a + 8b = 96. Next, subtract 4a + 8b = 70 from this equation. This result gives 8a = 26, which, solving for a, gives a = 3.25.Substitue the value of a into one of the original equations, which will give b = 7.125.Finally check your results by substituting the values of a and b into each equation.Answer:Given two equations 3a + 2b = 24 ------ (1) and 4a + 8b = 70 ------ (2) We have to solve this by using elimination method.Multiply the equation 3a + 2b = 24 by 4 on both the sides.We get 12a + 8b = 96 ---------- (3)Now, subtract the equation (2) from equation (3)12a + 8b = 96 ---------- (3)4a + 8b = 70 ---------- (2)--------------------------------(12a - 4a) + (8b - 8b) = (96 - 70)8a + 0 = 268a = 26a = 26/8a = 13/4 (Or) a = 3.25Substitute the value of a in the equation (2)4a + 8b = 70 ---------- (2)4(13/4) + 8b = 70.13 + 8b = 708b = 70 - 138b = 57b = 57/8 (Or) b = 7.125
first way is easy: 1000 minus 775 second way (might be the second way but not sure): minus 775 from 100 plus 225
(2,-2)
By elimination: x = 3 and y = 0
Simultaneous equations can be solved using the elimination method.
Yes and it works out that x = 3 and y = 4
x=1, y=1
When using the elimination method to solve a system of equations, you should add the equations if doing so will eliminate one variable. This typically occurs when the coefficients of that variable are opposites (e.g., +2 and -2). Conversely, you should subtract the equations if their coefficients are the same, which will also help to eliminate that variable. Ultimately, the goal is to manipulate the equations to create a situation where one variable cancels out.
You can solve lineaar quadratic systems by either the elimination or the substitution methods. You can also solve them using the comparison method. Which method works best depends on which method the person solving them is comfortable with.
Using the elimination method, 3x + (2y) times 18x - 3y - 5 gives the result of 36xy + 3x - 3y - 5.
4
To explain subtraction using the "ten to the top and ten to the bottom" method, start by illustrating how we can borrow from the next column to make subtraction easier. For example, if you have 52 - 28, you can take 10 from the 50 (making it 40) and add it to the 2 (making it 12). Now you can subtract 12 - 8 easily, which equals 4, and then subtract the tens: 40 - 20 equals 20. Finally, combine the results to find that 52 - 28 equals 24.
Add the equations: 4a + 4a - 5b + 5b = 7 + 17 ie 8a = 24 a = 3, so b = 1
One way to solve this system of equations is by using matrices. Form an augmented matrix in which the first 2x2 matrix is the coefficient matrix and the 2x1 matrix on its right is the answer. Now apply Gaussian Elimination and back-substitution. Using this method gives x=5 and y=1.