5x + 3y = -6
3x - 2y = 4 (multiply by 2 the first equation, multiply by 3 the second equation)
10x + 6y = -12
9x - 6y = 12 (add both the equations)
19x = 0 (divide by 19 both sides)
x = 0 (substitute 0 for x into the first equation)
5x + 3y = -6
5(0) + 3y = -6
3y = -6 (divide by 3 to both sides)
y = -2
Thus, (0, -2) is the solution of the given system of the equations.
Add the equations: 4a + 4a - 5b + 5b = 7 + 17 ie 8a = 24 a = 3, so b = 1
True
8840-026
Two equations, two unknownsFirst, multiply 3a + 2b = 70 by 4. This gives the equation 12a + 8b = 96. Next, subtract 4a + 8b = 70 from this equation. This result gives 8a = 26, which, solving for a, gives a = 3.25.Substitue the value of a into one of the original equations, which will give b = 7.125.Finally check your results by substituting the values of a and b into each equation.Answer:Given two equations 3a + 2b = 24 ------ (1) and 4a + 8b = 70 ------ (2) We have to solve this by using elimination method.Multiply the equation 3a + 2b = 24 by 4 on both the sides.We get 12a + 8b = 96 ---------- (3)Now, subtract the equation (2) from equation (3)12a + 8b = 96 ---------- (3)4a + 8b = 70 ---------- (2)--------------------------------(12a - 4a) + (8b - 8b) = (96 - 70)8a + 0 = 268a = 26a = 26/8a = 13/4 (Or) a = 3.25Substitute the value of a in the equation (2)4a + 8b = 70 ---------- (2)4(13/4) + 8b = 70.13 + 8b = 708b = 70 - 138b = 57b = 57/8 (Or) b = 7.125
Graphing is not necessarily easier than elimination or substitution. If you are good at drawing graphs, and do not like algebra, then graphing is easier. However, elimination and substitution are much faster, and graphing can often get awkward when working with more complicated formulae.
(2,-2)
By elimination: x = 3 and y = 0
Simultaneous equations can be solved using the elimination method.
Yes and it works out that x = 3 and y = 4
To solve this system of equations using the elimination method, we need to eliminate one variable by adding or subtracting the two equations. By looking at the equations given (2y-2x-8 = 0 and 3y-18-3x = 0), we can choose to eliminate either the x or y variable. Let's choose to eliminate the x variable: Multiply the first equation by 3 and the second equation by 2 to make the coefficients of x the same: 6y - 6x - 24 = 0 6y - 36 - 6x = 0 Now we can subtract the second equation from the first equation to eliminate x: (6y - 6x - 24) - (6y - 36 - 6x) = 0 Simplify to get -12 = 0, which is a false statement. Therefore, the system of equations is inconsistent and has no solution.
x=1, y=1
You can solve lineaar quadratic systems by either the elimination or the substitution methods. You can also solve them using the comparison method. Which method works best depends on which method the person solving them is comfortable with.
Using the elimination method, 3x + (2y) times 18x - 3y - 5 gives the result of 36xy + 3x - 3y - 5.
4
Add the equations: 4a + 4a - 5b + 5b = 7 + 17 ie 8a = 24 a = 3, so b = 1
One way to solve this system of equations is by using matrices. Form an augmented matrix in which the first 2x2 matrix is the coefficient matrix and the 2x1 matrix on its right is the answer. Now apply Gaussian Elimination and back-substitution. Using this method gives x=5 and y=1.
True