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Using the (surprise, surprise) "point-slope formula". The slope of a line is m = (y2 - y1)/(x2 - x1). If we let y2 and x2 be the variables x and y and multiply by y, we get y - y1 = m(x - x1).
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The slope of the line below is 2 Write the point slope equation for the line using the coordinates of the labeled point 1 9?
The equation for a line of slope m going through point (Xo, Yo) is given by: y - Yo = m(x - Xo) So for line of slope 2 going through (1, 9) the equation is: y - 9 = 2(x - 1) ⇒ y = 2x + 7
Write the equation in slope-intercept form of the line that has a slope of -3 and contains the point -4 5?
The answe iss..... 6
Write the equation in slope intercept form of the line that has a slope of 3 and contains the point 2 5?
y=2x+1
How do I write the equation of the line that passes through the given point and is perpendicular to the given line Write the answer in slope-intercept form?
The standard equation for a straight line is y = mx + c. Let this be the equation of the original line. Note that m and c are known values. Let the given point coordinates be (a,b)Two straight lines are perpendicular if the product of their gradients (slopes) is -1.The slope (m1) of the perpendicular line is therefore m1 = -1/mWhen y = b then x = a so the equation for the perpendicular line is y = m1x + d, and substituting gives : b = -a/m + d and this will enable d to be calculated.NOTE : In the absence of information for the equation of the original line and the coordinates of the given point then this is a general rather than a specific answer.
What is the perpendicular equation that meets the line of 2 3 and 5 7 at its midpoint showing key aspects of work?
Here are the key steps:* Find the midpoint of the given line. * Find the slope of the given line. * Divide -1 (minus one) by this slope, to get the slope of the perpendicular line. * Write an equation for a line that goes through the given point, and that has the given slope.
