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Using Pythagoras theorem: 53.665' correct to 3 dp
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What rectangle with the perimeter of 52 but has a different area of 48?
2*24
What is the length in feet of the diagonal of a rectangle when one side is greater than the other side by 24 inches and has an area of 6912 square inches showing work?
Convert the inches into feet which are 24/12 = 2 ft and 6912/144 = 48 sq ft Let the sides be x+2 and x:- As an equation: (x+2)*x = 48 As a quadratic equation: x2+2x-48 = 0 Factorising: (x-6)(+8) = 0 Solution: x = 6 or x = -8 so x = 6 because you can't have negative dimensions Therefore: (6+2)*6 = 48 sq ft Using Pythagoras' theorem: 82+62 = 100 and its square root is 10 Answer: diagonal is 10 feet long
48 hours is equal to how many days?
Each day is 24 hours long. 48/24 = 2 Therefore, 48 hours equals 2 days.
The length of a rectangle is twice the width width the perimeter is 48 in find the dimensions of the rectangle?
If the length of a rectangle is twice its width and it has a perimeter of 48, then the rectangle is 16 in length and 8 in width.
If you have a rectangular vegetable garden that is 24 feet long and 12 feet wide and wants to put fencing around the garden how much fencing will you need?
This problem requires that you find the perimeter of the rectangle. As we know a rectangle has 4 sides with two sets of sides that are the same length. so two that are 24 ft. and two that are 12 feet. add them up: 24+24+12+12=72 ft.
What is the diagonal of a rectangle with the length of 89.5 inches and a width of 48 inches?
The diagonal of a rectangle with the length of 89.5 inches and a width of 48 inches is approximately 101.6 inches.
Width of a rectangle is 6 and the diagonal is 10 what is the area?
A = 48 units2
What is length of diagonal line in a rectangle 48 feet by 36 feet?
60 feet Solved with the help of Pythagoras' theorem
What is the area of a square that is 24 feet long and 48 feet high?
No square can be 24 feet long and 48 feet high. All 4 sides of a square must bethe same length. If they're not, then it isn't a square.The area of a rectangle that is 24 feet long and 48 feet high is 1,152 square feet.
What rectangle with the perimeter of 52 but has a different area of 48?
2*24
The diagonal of the rectangle is 15cm find the length of the longest side which has sa shorter side of 9cm?
a rectangle had a perimeter of 48 and the longest side is 15 find the lenght of a shorter side
What is the diagonal measurement of a rectangle measuring 28 feet by 40 feet?
Sqrt(282 + 402) = a whisker under 48 ft 10 in
What are the factors of 48 that make a rectangle?
48 and 1 24 and 2 16 and 3 12 and 4 8 and 6
If a rectangle has a perimeter of 114 inches and a base of 24 inches what is the height of the rectangle and what is its area?
Perimeter of a rectangle (P) = 2b+2h = 2*24+2h=114 48+2h=114 2h=66 h=33" Area of a rectangle (A) = b*h = 24*33= 1584 sq. in.
How long is 24 - 48 hours in a day?
-24
What is the length in feet of the diagonal of a rectangle when one side is greater than the other side by 24 inches and has an area of 6912 square inches showing work?
Convert the inches into feet which are 24/12 = 2 ft and 6912/144 = 48 sq ft Let the sides be x+2 and x:- As an equation: (x+2)*x = 48 As a quadratic equation: x2+2x-48 = 0 Factorising: (x-6)(+8) = 0 Solution: x = 6 or x = -8 so x = 6 because you can't have negative dimensions Therefore: (6+2)*6 = 48 sq ft Using Pythagoras' theorem: 82+62 = 100 and its square root is 10 Answer: diagonal is 10 feet long
If the area of a rectangle is 48 and the length is 6 what is the width of the rectangle?
The width of the rectangle is 8. 48/6 = 8
