2*24
Convert the inches into feet which are 24/12 = 2 ft and 6912/144 = 48 sq ft Let the sides be x+2 and x:- As an equation: (x+2)*x = 48 As a quadratic equation: x2+2x-48 = 0 Factorising: (x-6)(+8) = 0 Solution: x = 6 or x = -8 so x = 6 because you can't have negative dimensions Therefore: (6+2)*6 = 48 sq ft Using Pythagoras' theorem: 82+62 = 100 and its square root is 10 Answer: diagonal is 10 feet long
Each day is 24 hours long. 48/24 = 2 Therefore, 48 hours equals 2 days.
If the length of a rectangle is twice its width and it has a perimeter of 48, then the rectangle is 16 in length and 8 in width.
The LCM of 24 and 48 is 48.Since 48 is a multiple of 24, it is automatically the LCM.48
The diagonal of a rectangle with the length of 89.5 inches and a width of 48 inches is approximately 101.6 inches.
A = 48 units2
No square can be 24 feet long and 48 feet high. All 4 sides of a square must bethe same length. If they're not, then it isn't a square.The area of a rectangle that is 24 feet long and 48 feet high is 1,152 square feet.
60 feet Solved with the help of Pythagoras' theorem
2*24
a rectangle had a perimeter of 48 and the longest side is 15 find the lenght of a shorter side
Sqrt(282 + 402) = a whisker under 48 ft 10 in
48 and 1 24 and 2 16 and 3 12 and 4 8 and 6
Perimeter of a rectangle (P) = 2b+2h = 2*24+2h=114 48+2h=114 2h=66 h=33" Area of a rectangle (A) = b*h = 24*33= 1584 sq. in.
-24
Convert the inches into feet which are 24/12 = 2 ft and 6912/144 = 48 sq ft Let the sides be x+2 and x:- As an equation: (x+2)*x = 48 As a quadratic equation: x2+2x-48 = 0 Factorising: (x-6)(+8) = 0 Solution: x = 6 or x = -8 so x = 6 because you can't have negative dimensions Therefore: (6+2)*6 = 48 sq ft Using Pythagoras' theorem: 82+62 = 100 and its square root is 10 Answer: diagonal is 10 feet long
The width of the rectangle is 8. 48/6 = 8