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Using Pythagoras theorem: 53.665' correct to 3 dp

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Q: How long is diagonal of 24' x 48' rectangle?
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What is the diagonal of a rectangle with the length of 89.5 inches and a width of 48 inches?

The diagonal of a rectangle with the length of 89.5 inches and a width of 48 inches is approximately 101.6 inches.


Width of a rectangle is 6 and the diagonal is 10 what is the area?

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What is the area of a square that is 24 feet long and 48 feet high?

No square can be 24 feet long and 48 feet high. All 4 sides of a square must bethe same length. If they're not, then it isn't a square.The area of a rectangle that is 24 feet long and 48 feet high is 1,152 square feet.


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The diagonal of the rectangle is 15cm find the length of the longest side which has sa shorter side of 9cm?

a rectangle had a perimeter of 48 and the longest side is 15 find the lenght of a shorter side


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If a rectangle has a perimeter of 114 inches and a base of 24 inches what is the height of the rectangle and what is its area?

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What is the length in feet of the diagonal of a rectangle when one side is greater than the other side by 24 inches and has an area of 6912 square inches showing work?

Convert the inches into feet which are 24/12 = 2 ft and 6912/144 = 48 sq ft Let the sides be x+2 and x:- As an equation: (x+2)*x = 48 As a quadratic equation: x2+2x-48 = 0 Factorising: (x-6)(+8) = 0 Solution: x = 6 or x = -8 so x = 6 because you can't have negative dimensions Therefore: (6+2)*6 = 48 sq ft Using Pythagoras' theorem: 82+62 = 100 and its square root is 10 Answer: diagonal is 10 feet long


If the area of a rectangle is 48 and the length is 6 what is the width of the rectangle?

The width of the rectangle is 8. 48/6 = 8