There are 9C3 = 10*9*8/(3*2*1) = 120 of them.
There are 9C3 = 84 combinations.
i would like a list all possible 4 digit combination using 0-9
There are 210 4 digit combinations and 5040 different 4 digit codes.
In other words, how many 4 digit combination locks are there using the digits 0-9 on each wheel. There are 10×10×10×10 = 10⁴ = 10,000 such combinations.
To calculate the number of different 4-digit combinations that can be made using numbers 0 through 9, we use the concept of permutations. Since repetition is allowed, we use the formula for permutations with repetition, which is n^r, where n is the number of options for each digit (10 in this case) and r is the number of digits (4 in this case). Therefore, the number of different 4-digit combinations that can be made using numbers 0 through 9 is 10^4, which equals 10,000 combinations.
There are 9C3 = 84 combinations.
There are 5,040 combinations.
i would like a list all possible 4 digit combination using 0-9
it's 610, which is 60,466,176. Since each digit spot could be anything 0-9 there are 10 numbers to try for each digit, making it 610.
106 or a million.
There are 210 4 digit combinations and 5040 different 4 digit codes.
9
There are ten combinations: one each where one of the ten digits, 0-9, is excluded.
Exactly 3,628,800, or 10!.
There are a total of 1,000 three-digit combinations from 000 to 999. This includes all combinations where the digits can range from 0 to 9, allowing for repetitions. Each of the three digit positions can have 10 possible values (0-9), leading to (10 \times 10 \times 10 = 1,000) combinations.
10,000 combinations.
10!/3! = 604800 different combinations.