If the digits are allowed to be repeated, there are six choices for each of the four digits
in the result, so the answer is 6 x 6 x 6 x 6 = 1296.
If the digits may not be repeated, the number of choices decreases with each successive digit, so there are 6 x 5 x 4 x 3 = 360 possibilities.
The word "combination" is, strictly speaking, a choice without repetition in which the order of selection does not matter (e.g., 1234 is considered the same as 4321). Since each of the 360 permutations counted above contains every combination in 24 possible orders, there are just 360/24 = 15 possible combinations.
You can make 5 combinations of 1 number, 10 combinations of 2 numbers, 10 combinations of 3 numbers, 5 combinations of 4 numbers, and 1 combinations of 5 number. 31 in all.
There are 24C12 = 24!/[12!*12!] = 2,704,156 combinations.
120 5x4x3x2x1=120
The answer will depend on how many digits there are in each of the 30 numbers. If the 30 numbers are all 6-digit numbers then the answer is NONE! If the 30 numbers are the first 30 counting numbers then there are 126 combinations of five 1-digit numbers, 1764 combinations of three 1-digit numbers and one 2-digit number, and 1710 combinations of one 1-digit number and two 2-digit numbers. That makes a total of 3600 5-digit combinations.
It depends. If you can only use each number once, there are 720 combinations. If you can use numbers multiple times, then there are 1000 combinations, by using all numbers from 000 to 999.
You can make 5 combinations of 1 number, 10 combinations of 2 numbers, 10 combinations of 3 numbers, 5 combinations of 4 numbers, and 1 combinations of 5 number. 31 in all.
There are 8,592,039,666 combinations of 6 numbers out of 138 numbers, like the numbers from 1 to 138.
14 * * * * * Wrong! There are 15. 4 combinations of 1 number, 6 combinations of 2 number, 4 combinations of 3 numbers, and 1 combination of 4 numbers.
10 * * * * * That is just plain wrong! It depends on how many numbers in each combination but there are 1 combination of 4 numbers out of 4, 4 combinations of 3 numbers out of 4, 6 combinations of 2 numbers out of 4, 4 combinations of 1 number out of 4. A grand total of 15 (= 24-1) combinations.
Oh, dude, let me break it down for you. So, you've got 44 numbers to choose from, right? And you're looking for 3-number combinations? Well, you can calculate that using the formula for combinations, which is like 44 choose 3. So, the answer is 44 x 43 x 42 divided by 3 x 2 x 1, which equals... wait, you want me to do the math too? Come on, man, I'm a comedian, not a human calculator!
There are 15380937 of them.
Number of combinations = 45C6 = 45!/6!(45-6)! = 8,145,060
There are 24C12 = 24!/[12!*12!] = 2,704,156 combinations.
900000
300
9
just intrested in the number combinations * * * * * Number of combinations = 56C6 = 56*55*54*53*52*51/(6*5*4*3*2*1) = 32,468,436