There are 15 combinations.
3*5=15 5*3=15 15*1=15
The three odd numbers that add up to 43 are 13, 15, and 15. This is because 13 + 15 + 15 = 43. These numbers are odd because they are not divisible by 2, and their sum equals 43, satisfying the condition of the question.
Numbers are unique so that only 15 is equal to 15. However, the limit of 14.999... repeating is 15.
10 000 * * * * * NO! That is the number of PERMUTATIONS, not COMBINATIONS. In a combination, the order does not matter so that 1234 is the same as 1432 or 3412 etc. Assuming the 4 numbers are different, the correct answer is 15 comprising 4 1-digit combinations, 6 2-digit combinations, 4 3-digit combinations and 1 4-digit combination. Another way to look at it is that the first number can be in a combination or not. With each of these possibilities, the second can be in or out - giving 2*2 = 4 ways so far. With each of these there are two options for the third giving 2*2*2 = 8 combinations so far and then the last number makes it 2*2*2*2 = 16. But one of these combinations contains none of the numbers - each one is not in. Leaving that one out gives the answer 15. In general, the number of combinations of any size, from n distinct objects is 2n and if you exclude the null combination, it is 2n - 1.
15
There are 15 combinations.
7
10 * * * * * That is just plain wrong! It depends on how many numbers in each combination but there are 1 combination of 4 numbers out of 4, 4 combinations of 3 numbers out of 4, 6 combinations of 2 numbers out of 4, 4 combinations of 1 number out of 4. A grand total of 15 (= 24-1) combinations.
16 x 15 / 2 ie 120
Assuming that the six numbers are different, the answer is 15.
14 * * * * * Wrong! There are 15. 4 combinations of 1 number, 6 combinations of 2 number, 4 combinations of 3 numbers, and 1 combination of 4 numbers.
15 choose 3 = 15!/(3!*(15-3)!) = 15!/(3!*12!) = (15*14*13)/(3*2) = 5*7*13 = 455
it is hard to say there are lot of combinations belive or not * * * * * If the previous answerer thinks 15 is a lot then true. There are 1 combination of 4 numbers out of 4, 4 combinations of 3 numbers out of 4, 6 combinations of 2 numbers out of 4, 4 combinations of 1 number out of 4. A grand total of 15 (= 24-1) combinations. Not so hard to say!
3*5=15 5*3=15 15*1=15
There are 15C3 = 15*14*13/(3*2*1) = 455 combinations, and I am NOT even going to try listing them.
It gives you the amounts of combinations of numbers from a set of numbers. For example if you wanted to find how many combinations of 2 numbers can you get from 6 numbers you would do this: =COMBIN(6,2) It will give the result 15, because there are 15 combinations as follows, where we are getting combinations of 2 numbers from the numbers 1 to 6: 1,2 1,3 1,4 1,5 1,6 2,3 2,4 2,5 2,6 3,4 3,5 3,6 4,5 4,6 5,6