How many combinations of 5 numbers are there for 1-30?

Answer 1

The number of combinations of r numbers out of n is

nCr = n!/[r!*(n-r)!] where n! = 1*2*3...*n

So here n = 30, r = 5 which gives

30*29*28*27*26/(5*4*3*2*1) = 142,506