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How many combinations of the numbers 1 and 4 can there be using four digits?
Wiki User
∙ 15y ago
Think of either using or not using the numbers 1 and 4 for each digit. For example, let ____ ____ _____ ____ be the 4 digit number, now 1 can either go in to the first spot or 4 can. So there are 2 choices for that spot, and similarly two for the next spot and the next and the last. So there are 2^4 =16 combinations of 1 and 4 if we make 4 digit numbers. (this uses the multiplication rule) To help a little more to see it, look at just the two digit number, It should have 2^2=4 choices by the logic above. Here they are: 11,14,41,44 and that's it!. See how we had two choices for each digit?
Wiki User
∙ 15y ago
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How many 4 number combinations are their using numbers 2-6?
If each number can be used only once then there are just four: 2345, 2346, 2456 and 3456. There are no others because the order of the digits does not matter in combinations.
What are the possible different combinations of numbers in four digits?
If the numbers contain zeros, the total number of combinations is 10,000. You can work this out easily logically: For ten single-digit numbers (0,1,2,3,4,5,6,7,8,9) then there are 10 possible 'combinations' For numbers with 2 digits then for each possible digit in the 10s column (e.g. in the 20s range) there are another 10 possible combinations (20,21,22,23,24,25,26,27, 28,29). As there are 10 possible ranges (single digits, teens, twenties, thirties etc) there will be 10 X 10 or 100 possible combinations. using the same logic, for three digits, there will be 10 X 10 X 10 or 1000 digits. And for 4 digits there will be 10 x 10 x 10 x 10 = 10,000 possible combinations. So for a number, say, with x digits, the total number of combinations of those digits will be 10 x 10 x 10..... etc with x numbers of 10s in the calculation. You can find out the number of combinations of any set of letters or numbers in the same way. as an example, to find out, say, the possible combinations of letters in the alphabet of 26 letters, then using the same method this can be given as 26 x 26 x 26 x 26............. with 26 '26's' in a row multiplied together. This gives the staggering amount of approximately 615612 followed by 31 zeros.
How many four digits numbers can be formed using 0578?
If the digits are all different then 18. Otherwise, 192.
How many whole numbers have exactly four digits?
how many numbers exactly have 4 digits ? 8900, 8999, 9000, 9999
How many 4 digit combinations are there for numbers 0 to 9?
-- If you're allowed to repeat digits in one combination,then there are 104 = 10,000 possibilities.-- If all four of the digits must be different, then there are(10 x 9 x 8 x 7) = 5,040 possibilities.
How many combinations of four digits can be made from 1-44?
45
How many combinations of four digits can be made from the numbers 1-9?
10
How many combinations for four numbers using four numbers?
4!=4x3x2x1=24
How many 4 number combinations are their using numbers 2-6?
If each number can be used only once then there are just four: 2345, 2346, 2456 and 3456. There are no others because the order of the digits does not matter in combinations.
How many combinations of numbers can you get with 1189 with one repeating?
You can get only four combinations: They are: 11, 118, 119 and 1189. In a combination, the order of the digits does not matter.
How many four digits combinations can be made using 2 - 7 - 9?
3 x 3 x 3 x 3 = 81 combinations
How many 4 digit numbers combinations can be made using 1234567?
Not repeating, it is 7*6*5*4 which is 840 ways ---- There are 7 choices for each of four digits, right? 74 = 2401
What are the possible different combinations of numbers in four digits?
If the numbers contain zeros, the total number of combinations is 10,000. You can work this out easily logically: For ten single-digit numbers (0,1,2,3,4,5,6,7,8,9) then there are 10 possible 'combinations' For numbers with 2 digits then for each possible digit in the 10s column (e.g. in the 20s range) there are another 10 possible combinations (20,21,22,23,24,25,26,27, 28,29). As there are 10 possible ranges (single digits, teens, twenties, thirties etc) there will be 10 X 10 or 100 possible combinations. using the same logic, for three digits, there will be 10 X 10 X 10 or 1000 digits. And for 4 digits there will be 10 x 10 x 10 x 10 = 10,000 possible combinations. So for a number, say, with x digits, the total number of combinations of those digits will be 10 x 10 x 10..... etc with x numbers of 10s in the calculation. You can find out the number of combinations of any set of letters or numbers in the same way. as an example, to find out, say, the possible combinations of letters in the alphabet of 26 letters, then using the same method this can be given as 26 x 26 x 26 x 26............. with 26 '26's' in a row multiplied together. This gives the staggering amount of approximately 615612 followed by 31 zeros.
How many four digits numbers can be formed using 0578?
If the digits are all different then 18. Otherwise, 192.
What are the combinations of 1 through 10 with out using them twice?
There is 1 combination of all ten numbers, 10 combinations of one number and of nine numbers, 45 combinations of two or eight numbers, 120 combinations of three or seven numbers, 210 combinations of four or six numbers and 252 combinations of five numbers. That is 1023 = 210 - 1 in total.
How many different combinations can you make using 2 3 6 and 9?
If you use them only once each, you can make 15 combinations. 1 with all four digits, 4 with 3 digits, 6 with 2 digits, and 4 with 1 digit. There is also a combination containing no digits making 16 = 24 combinations from 4 elements.
What rule must be used to find the number of strings of four decimal digits that do not contain the same digit twice?
It is the number of combinations of four numbers where the number of available digits starts at 10 and reduces by 1 each time.
