1 acre = 43,560 sq ft
→ volume pond (liquid) = 3/4 x 43,560 sq ft x 6 ft = 196,020 cu ft
* In UK: 196,020 cu ft ≈ 1,220,976 imp gal
* In US: 196,020 cu ft ≈ 1,466,331 US gal
1 acre = 43,560 square feet1 acre 5 feet deep = 43,560 x 5 = 217,800 cubic feet = 1,629,257 gallons (rounded)
1 acre = 43,560 square feet If the sides of the pond are straight ... its cross section area is 1/4 acre all the way down to the bottom ... then its volume is (43,560/4) x (5) = 54,450 cubic feet = 407,314.3 gallons
1 acre = 43,500 ft2vol = area * depth = 43,500*5 = 217,500 ft31 ft3 is approx. 7.48 gallons217,500 ft3 * (7.48 gal/ft3) = 1,626,900 gallons
1 acre = 43,560 square feet1 cubic foot = 1,728 cubic inches1 gallon = 231 cubic inchesVolume of the lake = (1.5 x 43,560) x (5) = 326,700 cubic feet = 2,443,885.7 gallons (rounded)
how many gallons of water does a swimming pool 15 feet by 4 feet deep hold
There are 27,154 gallons of water in one acre of land that is one inch deep.
1 acre = 43560 sq.feet. 1 foot deep water over an acre is 43560 cubic feet, which is 325851.4 gallons in 1 foot deep. If it is 1 inch deep (1/12 foot) then it is 27154.3 gallons in 1 inch deep.
It depends on the depth of the water. Assuming the water in one inch deep, there would be about 13,577 gallons of water in the half acre.
A 1000 acre lake that is 7 feet deep (uniformly) will have 7000 acre feet of water in it. An acre foot is an acre of water one foot deep, and the unit is used to measure reservoir water capacity. The conversion factor is that one acre foot equals about 325,851.5 gallons. The lake in question is holding 7000 times 325,851.5 gallons of water.
27,154
The answer will depend on how deep the lake is!
Approximately 8,146,286 gallons of water.
If the pond is uniformly 6-feet deep it would contain about 1,955,109 gallons of water.
Approximately 48,878,000 gallons.
Approximately 977,553 gallons of water.
A 25-acre pond that is uniformly 6 feet deep will hold about 48,877,714 gallons of water.
One acre-foot is 325,851.4 US gallons of water.