There are only 10 combinations. In each combination one of the 10 digits is left out.
9
In most 3-number locks, each number ring offers a choice of 10 digits, from 0 to 9. I that case, there are 103 = 1000 combinations.
10000
There are 10 digits, 0, 1, 2, 3, 4, 5, 6, 7, 8, and 9. Let's say that a three digits number has a form of xyz. There are only 9 possibilities for x (0 cannot be in the first place), 10 possibilities for y, and 10 possibilities for z. So there are 9 x 10 x 10 = 900 combinations. However, there are only 9 digits from 1 to 9. So we have 9 possibilities for x, y, and z. Hence, there are 9 x 9 x 9 = 729 combinations.
There are different numbers of combinations for groups of different sizes out of 9: 1 combination of 9 digits 9 combinations of 1 digit and of 8 digits 36 combinations of 2 digits and of 7 digits 84 combinations of 3 digits and of 6 digits 126 combinations of 4 digits and of 5 digits 255 combinations in all.
There are only 10 combinations. In each combination one of the 10 digits is left out.
9
There are 167960 9 digits combinations between numbers 1 and 20.
Since 0 cannot be in the first place of the 4-digits number, we have 9 x 10 x 10 x 10 = 9,000 combinations.
1000
Perhapsf you specified the number of digits. e.g. 0-9 with two digits.
In most 3-number locks, each number ring offers a choice of 10 digits, from 0 to 9. I that case, there are 103 = 1000 combinations.
0000-9999 (10x10x10x10 or 104) = 10,000 possible combinations allowing for repeated digits. If you are not able to repeat digits then it's 10 x 9 x 8 x 7 or 5,040 possible combinations without repeated digits.
9.
pls i need the formular of national game lotto
That depends on how many of the digits are repeated. If no digits are repeated, you have 9 choices for the first digit, 8 choices for the second, etc.; for a total of 9 x 8 x 7 x 6 x 5 x 4.