0
All the numbers from 100,000 to 111,111 contain a zero, so that is 11,111 numbers already. The question is then how many numbers between 1,111 and 2,000 contain at least one zero. There are 19 numbers every hundred digits from 1,200 onwards that meet this requirement (10 which have a 0 in the tens and ten which have a 0 in the units, not counting 00 twice) and thus we have 19x8 = 152 additional numbers. Add this to the amount from before, and 1 for the end value of 112,000: 11,111+152+1 = 11,264 numbers.
Still curious? Ask our experts.
Chat with our AI personalities
Professor
Fran
Blake
Add your answer:
Earn +20 pts
What are the greatest and least 6 digit numbers in which the digit in the ten thousands place is twice the digit in the tens place?
Greatest: 989949 Least: 100000
How many integers from 1 to 100000 contain the digit 6 at least once?
Oh, isn't that a happy little question! To find the number of integers from 1 to 100,000 that contain the digit 6 at least once, we can think about it like painting a beautiful landscape. We can first count the numbers that do not have the digit 6, which are the numbers from 1 to 9,999. There are 10,000 numbers that do not have the digit 6. Then, we subtract this from the total numbers from 1 to 100,000 to find the answer. Happy counting!
What proportion of the first 10000 natural numbers contain a 5?
271 of the first 1000 natural numbers contain at least one digit 5. That is 27.1 % of them.
How many three digit numbers contain at least two sevens?
27: 077,177,277,377,477,577,677,877,977,717,727,737,747,757,767,777,787,797
How many seven digit numbers contain the number seven at least once?
To find the total number of seven-digit numbers that contain the number seven at least once, we can use the principle of complementary counting. There are a total of 9,999,999 seven-digit numbers in total. To find the number of seven-digit numbers that do not contain the number seven, we can count the number of choices for each digit (excluding seven), which is 9 choices for each digit. Therefore, there are 9^7 seven-digit numbers that do not contain the number seven. Subtracting this from the total number of seven-digit numbers gives us the number of seven-digit numbers that contain the number seven at least once.
