All the numbers from 100,000 to 111,111 contain a zero, so that is 11,111 numbers already. The question is then how many numbers between 1,111 and 2,000 contain at least one zero. There are 19 numbers every hundred digits from 1,200 onwards that meet this requirement (10 which have a 0 in the tens and ten which have a 0 in the units, not counting 00 twice) and thus we have 19x8 = 152 additional numbers. Add this to the amount from before, and 1 for the end value of 112,000: 11,111+152+1 = 11,264 numbers.
Greatest: 989949 Least: 100000
271 of the first 1000 natural numbers contain at least one digit 5. That is 27.1 % of them.
There is only one number and that is 123456.
27: 077,177,277,377,477,577,677,877,977,717,727,737,747,757,767,777,787,797
9*10*10*10*10 - 8*9*9*9*9
Only one. 123456.
Greatest: 989949 Least: 100000
theres only 1 number which is 123456, the least digit is 1 and the greatest is 6
271 of the first 1000 natural numbers contain at least one digit 5. That is 27.1 % of them.
Equation
252
There is only one number and that is 123456.
27: 077,177,277,377,477,577,677,877,977,717,727,737,747,757,767,777,787,797
9*10*10*10*10 - 8*9*9*9*9
i think alot like 100 at least
46000
252