There are 5P3 = 5!/2! = 5*4*3 = 60 permutations.
The distinguishable permutations are the total permutations divided by the product of the factorial of the count of each letter. So: 9!/(2!*2!*1*1*1*1*1) = 362880/4 = 90,720
because permutations are order specific, and because there are two d's "dad" counts as only one. so it is 6 (3P3)/2 (there are two d's) so the answer is 3 DAD ADD DDA
Take the total number of letters factorial, then divide by the multiple letters factorial (a and e). 7! / (2!*2!) or 1260.
Not quite. Number of combinations is 20, number of permutations is 10. Any 2 from 5 is 10 but in any order doubles this.
2
239,500,800 12!/2! * * * * * Actually, as the word "permutation" [not permutations] has 11 letters, the answer is 11!/2! = 19,958,400
11!/(2!*2!*2!) = 4,989,600
4! Four factorial. 4 * 3 * 2 = 24 permutations ------------------------
There are 4*3*2*1 = 24 of them.
The word mathematics has 11 letters; 2 are m, a, t. The number of distinguishable permutations is 11!/(2!2!2!) = 39916800/8 = 4989600.
There are 6!/(2!*3!) = 60
LOLLIPOP = 8 letters L=3 O=2 I=1 P=2 number of permutations = 8!/3!2!2! = 8x7x6x5x4x3x2 / 3x2x2x2 = 40320 /24 = 1680
geometry has 8 letters, 2 of which are the same (e) So, the answer is 8!/2! = 20,160
4! 4 * 3 * 2 * 1 = 24
We know there are 10! (ten factorial) permutations (that's about 3,628,800 permutations); however, we know that number includes repeated permutations, as there are 3 s', 3 t's and 2 i's. So we have to divide by the number of ways these can be written as individual permutations (if they were considered as unique elements), which are 3! (= 6), 3! and 2! (= 2) respectively. So our final calculation would be 3628800 / (6 * 6 * 2) = 50400 unique permutations.
The number of permutations of the letters EFFECTIVE is 9 factorial or 362,880. To determine the distinct permutations, you have to compensate for the three E's (divide by 4) and the two F's (divide by 2), giving you 45,360.