In three flips of a fair coin, there are a total of 8 possible outcomes: T, T, T; T, T, H; T, H, T; T, H, H; H, H, H; H, H, T; H, T, H; H, T, T Of the possible outcomes, four of them (half) contain at least two heads, as can be seen by inspection. Note: In flipping a coin, there are two possible outcomes at each flipping event. The number of possible outcomes expands as a function of the number of times the coin is flipped. One flip, two possible outcomes. Two flips, four possible outcomes. Three flips, eight possible outcomes. Four flips, sixteen possible outcomes. It appears that the number of possible outcomes is a power of the number of possible outcomes, which is two. 21 = 2, 22 = 4, 23 = 8, 24 = 16, .... Looks like a pattern developing there. Welcome to this variant of permutations.
7/8
130 instances of 3 heads out of 1024 total possible outcomes=130/1024=0.126953125
The probability of flipping Heads on a coin is 1 - a certainty - if the coin is flipped often enough. On a single toss of a fair coin the probability is 1/2.
For a fair coin it is (1/2)3 = 1/8 = 0.125For a fair coin it is (1/2)3 = 1/8 = 0.125For a fair coin it is (1/2)3 = 1/8 = 0.125For a fair coin it is (1/2)3 = 1/8 = 0.125
Heads or tails; each have a probability of 0.5 (assuming a fair coin).
In three flips of a fair coin, there are a total of 8 possible outcomes: T, T, T; T, T, H; T, H, T; T, H, H; H, H, H; H, H, T; H, T, H; H, T, T Of the possible outcomes, four of them (half) contain at least two heads, as can be seen by inspection. Note: In flipping a coin, there are two possible outcomes at each flipping event. The number of possible outcomes expands as a function of the number of times the coin is flipped. One flip, two possible outcomes. Two flips, four possible outcomes. Three flips, eight possible outcomes. Four flips, sixteen possible outcomes. It appears that the number of possible outcomes is a power of the number of possible outcomes, which is two. 21 = 2, 22 = 4, 23 = 8, 24 = 16, .... Looks like a pattern developing there. Welcome to this variant of permutations.
3 of them.
Sample space: {hhh,hht,hth,htt,ttt,tth,tht,thh} 8 possible outcomes
Each toss has 2 outcomes; so the number of outcomes for 3 tosses is 2*2*2 = 8
A probability is fair if there is no bias in any of the possible outcomes. Said another way, all of the possible outcomes in a fair distribution have an equal probability.
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Can you PLEASE help me with this problem:Suppose a fair coin is flipped twice and the following payoffs are assigned to each of the 4 possible outcomes: H-H:win20; H-T: win 9; T-H:lose 7; T-T: lose 16what is the ecepected value of the gamble?What is the probablity of each event?Is the gamble fair?
Normally there would considered to be 2⁴ = 16 possible outcomes as each outcome is one of 2 states: Head or Tails. ------------------------- There is an extremely small probability that a normal coin will end up on its edge, which mean there are 3⁴ = 81 possible outcomes. However, this probability is so small that it is ignored and normally only 2 outcomes are considered possible. As the radius to width ratio of the coin changes, the probability of the coin ending up on its edge changes, for some values being so significant that it becomes a real probability that the edge can result, and for some ratios it is almost always the edge that results and the probability of head or tails (ie ends of the cylinder that is the coin) is so small as to be ignored like the edge for a normal sized coin (cylinder).
Assuming the coins are fair, two-sided coins, and landing on their sides is not an option, there are four possible outcomes if you consider coin a having a head and coin b having a tail being a different instance from coin a being a tail and coin be having a head. Here they are; Coin A | Coin B Heads | Tails Heads | Heads Tails....| Heads Tails....| Tails
7/8
130 instances of 3 heads out of 1024 total possible outcomes=130/1024=0.126953125