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Find the roots of the polynomial given 4x2 - 3x - 5?
No integer roots. Quadratic formula gives 1.55 and -0.81 to the nearest hundredth.
What is x3 plus 4x2-3x-12 divided by x2-3?
(x3 + 4x2 - 3x - 12)/(x2 - 3) = x + 4(multiply x2 - 3 by x, and subtract the product from the dividend)1. x(x2 - 3) = x3 - 3x = x3 + 0x2 - 3x2. (x3 + 4x2 - 3x - 12) - (x3 + 0x2 - 3x) = x3 + 4x2 - 3x - 12 - x3 + 3x = 4x2 - 12(multiply x2 - 3 by 4, and subtract the product from 4x2 - 12)1. 4x(x - 3) = 4x2 - 12 = 4x2 - 122. (4x2 - 12) - (4x2 - 12) = 4x2 - 12 - 4x2 + 12 = 0(remainder)
Which two values of x are roots of the polynomial below x2-3x 5?
It is difficult to tell because there is no sign (+ or -) before the 5. +5 gives complex roots and assuming that someone who asked this question has not yet come across complex numbers, I assume the polynomial is x2 -3x - 5 The roots of this equation are: -1.1926 and 4.1926 (to 4 dp)
Can you put the equation x2 - 5 -4x2 plus 3x equals 0 in the form ax2 plus bx plus c equals 0?
x2-5-4x2+3x = 0 -3x2+3x-5 = 0 or as 3x2-3x+5 = 0
What polynomial is 3x -1 a factor of?
4
Find the roots of the polynomial given 4x2 - 3x - 5?
No integer roots. Quadratic formula gives 1.55 and -0.81 to the nearest hundredth.
What is the degree of this polynomial 4x2-3x 14-5x2 3x-7?
kjkjj
How many roots does the polynomial 3x5 2x3 3x have?
To find the roots of the polynomial (3x^5 + 2x^3 + 3x), we can factor out the common term, which is (x): [ x(3x^4 + 2x^2 + 3) = 0. ] This shows that (x = 0) is one root. The quartic polynomial (3x^4 + 2x^2 + 3) does not have real roots (as its discriminant is negative), meaning it contributes no additional real roots. Therefore, the polynomial has only one real root, which is (x = 0).
How do you factorise 4x2-6x-12?
4x2 - 6x - 12 = 2 (2x2 - 3x - 6) There are no integer roots, the approximate roots are 2.64 and -1.14
What is linear in 4x2 3x - 6?
4x2 + 3x - 6 is a second degree polynomial. Since the polynomial function f(x) = 4x2 + 3x - 6 has 2 zeros, it has 2 linear factors. Since we cannot factor the given polynomial, let's find the two roots of the equation 4x2 + 3x - 6 = 0, which are the zeros of the function. 4x2 + 3x - 6 = 0 x2 + (3/4)x = 6/4 x2 + (3/4)x + (3/8)2 = 6/4 + 9/64 (x + 3/8)2 = 105/64 x + 3/8 = ± √(105/64) x = (-3 ± √105)/8 x = -(3 - √105)/8 or x = -(3 + √105)/8 Thus, the linear factorization of f(x) = 4[x + (3 - √105)/8][x + (3 + √105)/8].
Example of third-degree polynomial?
pretty sure a third degree polynomial is just one that has a term to the power of 3 eg. x3 + 4x2 + 3x + 5
What are the roots of the polynomial function 3x2-13x 4?
(3x - 1)(x - 4) so roots are 1/3 and 4
What is x3 plus 4x2-3x-12 divided by x2-3?
(x3 + 4x2 - 3x - 12)/(x2 - 3) = x + 4(multiply x2 - 3 by x, and subtract the product from the dividend)1. x(x2 - 3) = x3 - 3x = x3 + 0x2 - 3x2. (x3 + 4x2 - 3x - 12) - (x3 + 0x2 - 3x) = x3 + 4x2 - 3x - 12 - x3 + 3x = 4x2 - 12(multiply x2 - 3 by 4, and subtract the product from 4x2 - 12)1. 4x(x - 3) = 4x2 - 12 = 4x2 - 122. (4x2 - 12) - (4x2 - 12) = 4x2 - 12 - 4x2 + 12 = 0(remainder)
Is the highest degree of any of the terms in the polynomial?
Yes, in a polynomial, the highest degree is determined by the term with the greatest exponent on its variable. For example, in the polynomial (3x^4 + 2x^2 - 5), the highest degree is 4, which comes from the term (3x^4). The degree of a polynomial is significant as it influences the polynomial's behavior and the number of roots it can have.
Y equals 4X2 plus 3x plus 8?
y=4x2+3x+8
What are the roots of the polynomial x2 plus 3x plus 5?
You can find the roots with the quadratic equation (a = 1, b = 3, c = -5).
Is 4-3x a polynomial?
7
