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Either 5040 or 210, depending on a whether order is important. Keep reading.

Four slots. First slot: 10 people to choose from 2nd slot: 9 people left (1 is already chosen) 3rd: 8 4th: 7

10*9*8*7=5040, assuming, of course, the people are chosen randomly and no one person can be on the committee twice.

But then we need to adjust this figure because there will be some duplication, since if Ben, George, Sue, and Jill are chosen for example, there are different ways that they can be chosen and all four of these same people are still on the committee. This is much like when Lotto balls are draw - you don't really care what order the balls are drawn as long as you match them up. So the number of ways that 4 people can be arranged in 4 positions is 4! = 4 x 3 x 2 x 1 = 24. So dividing 5040 by 24 will give you the number of possible committee selections, assuming that it doesn't matter which order they are chosen.

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210

Q: How many ways can a committee of 4 people be chosen from 10 people?

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6,375,600

20C2 = 190

The answer will depend on what "and to employees" means. Also, there is no information about the ten candidates. It they contain only one manager, for example, the answer is that the required committee cannot be chosen.The answer will depend on what "and to employees" means. Also, there is no information about the ten candidates. It they contain only one manager, for example, the answer is that the required committee cannot be chosen.The answer will depend on what "and to employees" means. Also, there is no information about the ten candidates. It they contain only one manager, for example, the answer is that the required committee cannot be chosen.The answer will depend on what "and to employees" means. Also, there is no information about the ten candidates. It they contain only one manager, for example, the answer is that the required committee cannot be chosen.

53,130 ways.

There are 14C8 = 14*13*12*11*10*9/(6*5*4*3*2*1) = 3003 ways.

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There are 9*8*7 = 504 ways.

125

309*308/2 = 47586

6,375,600

There are 8!/(4!*4!) = 70 ways.

20C2 = 190

I'm going with 25,200 3 men out of 10 may be chosen in 10C3 ways = 10 ! / 3! 7 ! = 120 ways. 4 women may be chosen out of 10 in 10C4 = 10 ! / 4! 6! ways = 210 ways. Therefore, a committee with 3 men and 4 women can be formed in 120 x 210 = 25,200 ways.

40 x 39 x 38 x 37 = 2193360

560.

There are 45360 ways.

It is: 15C7 = 6435 combinations

The answer will depend on what "and to employees" means. Also, there is no information about the ten candidates. It they contain only one manager, for example, the answer is that the required committee cannot be chosen.The answer will depend on what "and to employees" means. Also, there is no information about the ten candidates. It they contain only one manager, for example, the answer is that the required committee cannot be chosen.The answer will depend on what "and to employees" means. Also, there is no information about the ten candidates. It they contain only one manager, for example, the answer is that the required committee cannot be chosen.The answer will depend on what "and to employees" means. Also, there is no information about the ten candidates. It they contain only one manager, for example, the answer is that the required committee cannot be chosen.