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10x + 5

unless you know what x & y are

* * * * *

Perhaps this answer will be of help:

x3 + x2 + 5x + 5 = (x + 1)(x2 + 5).

If you are willing to go to complex roots, then,

x3 + x2 + 5x + 5 = (x + 1)(x2 + 5).

= (x + 1)(x + i√5)(x - i√5); in which case,

x = -1 or ±i√5.

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14y ago

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