There are some missing terms. First of all, I assume that A, B, and C are collinear and that B is between A and C.
If this is true then AC-AB=BC by the whole is the sum of its parts theorem.
24-20=4
Otherwise, all that can be said about BC is that it's length is between AC-AB = 4 and AC+AB = 44 units.
6.7
10
C minus B equals AB
associative property
2
If AC equals 6 and BD equals 4, then AB equals 5.
36
Since 36=24+1/2.24 and abc and pqr are similar, ab= 10+1/2.10=15.
24
yes
By use of the sine rule: sin A / BC = sin B / AC = sin C / AB Angles B and C are known, as is length AC, so: sin B / AC = sin C / AB AB = AC x sin C / sin B AB = 17cm x sin 24 / sin 95 ~= 6.94cm The ratios for the sine rule can also be given the other way up: BC / sin A = AC / sin B = AB / sin C (I learnt the rule the first way.) Further, if r is the radius of the triangle's circumcircle, then: sin A / BC = 1/2r or BC / sin A = 2r
Oh, dude, you're hitting me with some math here. Okay, so, like, if you have "ab" plus "ab," you're basically just adding the same thing twice, so it's like adding two apples plus two apples - you end up with four apples. So, "ab" plus "ab" equals "2ab." Math can be weirdly simple sometimes, right?
6.7
10
4... if you plug it in, it works
Reflexive.
Identity