There are some missing terms. First of all, I assume that A, B, and C are collinear and that B is between A and C.
If this is true then AC-AB=BC by the whole is the sum of its parts theorem.
24-20=4
Otherwise, all that can be said about BC is that it's length is between AC-AB = 4 and AC+AB = 44 units.
6.7
10
C minus B equals AB
No. A times B = AB
associative property
If AC equals 6 and BD equals 4, then AB equals 5.
36
Since 36=24+1/2.24 and abc and pqr are similar, ab= 10+1/2.10=15.
24
yes
By use of the sine rule: sin A / BC = sin B / AC = sin C / AB Angles B and C are known, as is length AC, so: sin B / AC = sin C / AB AB = AC x sin C / sin B AB = 17cm x sin 24 / sin 95 ~= 6.94cm The ratios for the sine rule can also be given the other way up: BC / sin A = AC / sin B = AB / sin C (I learnt the rule the first way.) Further, if r is the radius of the triangle's circumcircle, then: sin A / BC = 1/2r or BC / sin A = 2r
2ab
4... if you plug it in, it works
6.7
10
Reflexive.
Identity