Three people flip a coin and there are two possible outcome of a coin flip.
(Except in one of my favorite Twilight Zone episodes which begins: Mr. Hector B. Poole, resident of the Twilight Zone. Flip a coin and keep flipping it. What are the odds? Half the time it will come up heads, half the time tails. But in one freakish chance in a million, it'll land on its edge. Mr. Hector B. Poole, a bright human coin, on his way to the bank.)
Since we are not in The Twilight Zone, here is one way to see this.
Sam has two possible outcomes, Joe has two more possible out come, so that is 4 and Debbie has two more so that is 8. So there are 8 possible outcomes. This is 23 .
In case you want to see them, here are all the possible outcomes:
1.head head head
2.head head tail
3.head tail head
4.tail head head
5.tail tail head
6.head tail tail
7.tail head tail
8.tail tail tail
When there are just two possible outcomes with fixed probability ( 1/2 and 1/2 in this case) summing to one. These distributions are called are called binomial distributions.
In this case, it is 3C0+3C1+3C2+3C3=1+3+3+1=8 where 3CN is the number of ways to choose N things from 3. Note that this is also the 4th row in Pascals triangle.
I am guessing SamJoe, means SAM and JOE not one person, so three people flip a coin, we have two outcomes each times, so 23= 8 possible outcomes. If you had n people, there would be 2n outcomes. For example, if two people flip there are 4 outcomes HH TT HT or TH
There are sixteen different outcomes. To figure this you multiply the number of possible outcomes for each coin, which is 2 for all of them. So you take 2^4 which comes out to 16.
Normally there would considered to be 2⁴ = 16 possible outcomes as each outcome is one of 2 states: Head or Tails. ------------------------- There is an extremely small probability that a normal coin will end up on its edge, which mean there are 3⁴ = 81 possible outcomes. However, this probability is so small that it is ignored and normally only 2 outcomes are considered possible. As the radius to width ratio of the coin changes, the probability of the coin ending up on its edge changes, for some values being so significant that it becomes a real probability that the edge can result, and for some ratios it is almost always the edge that results and the probability of head or tails (ie ends of the cylinder that is the coin) is so small as to be ignored like the edge for a normal sized coin (cylinder).
Each coin can land in two ways.The die has 6 possible outcomes.So there are 2 x 2 x 6 = 24 possible outcomes for the whole experiment.Note that I am assuming the coins can be told apart - say the first coin and 2nd coin and that H and then T is different that T and then H. If not, then there are only be three outcomes for the coins-- 2 heads, 1 head or no heads and the total number of outcomes would be 3 X 6 = 18.
Each toss has 2 outcomes; so the number of outcomes for 3 tosses is 2*2*2 = 8
i think that it is possibly 8
I am guessing SamJoe, means SAM and JOE not one person, so three people flip a coin, we have two outcomes each times, so 23= 8 possible outcomes. If you had n people, there would be 2n outcomes. For example, if two people flip there are 4 outcomes HH TT HT or TH
Heads or tails; each have a probability of 0.5 (assuming a fair coin).
Two possible outcomes for each flip. 2,048 possible histories of 11 flips.
If you can identify the outcomes with who flipped each coin: eg Joe and Mary = Heads, Sam = Tails, then 23 = 8. Otherwise, 4.
We use three coins (quarter, nickel, dime) each are flipped only once. We get 8 possible outcomes (or four outcomes as an alternative).
There are sixteen different outcomes. To figure this you multiply the number of possible outcomes for each coin, which is 2 for all of them. So you take 2^4 which comes out to 16.
It is not. There are only two possible outcomes for each toss of a coin whereas the number of possible outcomes when selecting a marble from a bag will depend on the numbers of distinct marbles in each bag. The coin toss generates a binomial distribution the marbles experiment is multinomial.
The coin can result in one of two possibilities. For each of those . . .The cube has 6 possibilities.Total possibilities for the coin and the cube = 2 x 6 = 12 .
To represent all possible combinations of tossing a coin 5 times on a tree diagram, you would need 2^5 leaves, which equals 32 leaves. This is because each toss of a coin has 2 possible outcomes (heads or tails), and there are 5 tosses in total. Each branch on the tree diagram represents one possible outcome, leading to a total of 32 leaves to cover all possible combinations.
Each time you flip a fair coin it has the same equal chance of landing on heads or tails. That is, even if you get (for example) 19 heads in a row, the next flip still has 50% chance of landing on tails (if the coin is fair).
There are two outcomes for each coin and three coins; 2 x 2 x 2 = 23 = 8 outcomes.