y=2x-4 y=2x-5 y=1 1=2x-4 -2x = -5 x=2/5 the solution is (x,y) = (2/5,1)
2x - 3y = 142x - y = 10eqn (1) - eqn(2) gives: -2y = 4 so that y = -2Then, by eqn (2): 2x -(-2) = 102x + 2 = 102x = 8 and so x = 4The solution, therefore, is (x, y) = (4, -2)2x - 3y = 142x - y = 10eqn (1) - eqn(2) gives: -2y = 4 so that y = -2Then, by eqn (2): 2x -(-2) = 102x + 2 = 102x = 8 and so x = 4The solution, therefore, is (x, y) = (4, -2)2x - 3y = 142x - y = 10eqn (1) - eqn(2) gives: -2y = 4 so that y = -2Then, by eqn (2): 2x -(-2) = 102x + 2 = 102x = 8 and so x = 4The solution, therefore, is (x, y) = (4, -2)2x - 3y = 142x - y = 10eqn (1) - eqn(2) gives: -2y = 4 so that y = -2Then, by eqn (2): 2x -(-2) = 102x + 2 = 102x = 8 and so x = 4The solution, therefore, is (x, y) = (4, -2)
y = -1/(3x7 + 2x - 9)y = -(3x7 + 2x - 9)-1y' = -(-1)(3x7 + 2x - 9)-2(3x7 + 2x - 9)'y' = (3x7 + 2x - 9)-2(21x6 + 2)y' = (21x6 + 2)/(3x7 + 2x - 9)2
y-2x=3 -y -y -2x=3-y -3 -3 -2x-3=-y /-1 /-1 2x+3=y y=2x and y=2x+3 have the same slope of 2, so they are parallel. Hope this helps! ;D
2x / (y-2) + 2x / (2-y)First get a common denominator: (y-2) (2-y)Then you have:2x(2-y) / (y-2)(2-y) + 2x(y-2) / (y-2)(2-y), summing and simplifying, you get:(4x-4) / (y-2)(2-y)
y=2x-4 y=2x-5 y=1 1=2x-4 -2x = -5 x=2/5 the solution is (x,y) = (2/5,1)
If by that you mean x= 1 and y= 2 then yes (1,2) is a solution
The solution is: x = 1 and y = -1
2x - y = 2 2x - y = -2 This system is inconsistent -- that is, there is no solution. To help see why, let Z = 2x - y and notice Z can't be 2 and -2 at the same time.
2x-y=0 -y=-2x y=2x A line going through the origin and having a slope of 2. Sample answers are y is twice as much as x. y=2 when x=1
2x - 3y = 142x - y = 10eqn (1) - eqn(2) gives: -2y = 4 so that y = -2Then, by eqn (2): 2x -(-2) = 102x + 2 = 102x = 8 and so x = 4The solution, therefore, is (x, y) = (4, -2)2x - 3y = 142x - y = 10eqn (1) - eqn(2) gives: -2y = 4 so that y = -2Then, by eqn (2): 2x -(-2) = 102x + 2 = 102x = 8 and so x = 4The solution, therefore, is (x, y) = (4, -2)2x - 3y = 142x - y = 10eqn (1) - eqn(2) gives: -2y = 4 so that y = -2Then, by eqn (2): 2x -(-2) = 102x + 2 = 102x = 8 and so x = 4The solution, therefore, is (x, y) = (4, -2)2x - 3y = 142x - y = 10eqn (1) - eqn(2) gives: -2y = 4 so that y = -2Then, by eqn (2): 2x -(-2) = 102x + 2 = 102x = 8 and so x = 4The solution, therefore, is (x, y) = (4, -2)
If you mean: y = -8 and y = -2x-12 then the solution is x = -2 and y = -8
The solution to the equation y = 1/2x will be x= 2y.
There is one solution for x and one solution for y. The solution is: x = -1 ; y = 2
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For example, if you have (0, 6) or (3, 1). Which of them is a solution to y - 2x = 6? Check (0, 6): y - 2x = 6, substitute 0 for x, and 6 for y into the equation 6 - 2(0) =? 6 6 - 0 =? 6 6 = 6 True, then (0, 6) is a solution. Check (3, 1): y - 2x = 6, substitute 3 for x, and 1 for y into the equation 1 - 2(3) =? 6 1 - 6 =? 6 -5 = 6 False, then (3, 1) is not a solution.
Assuming that you are giving two separate equations:Your answer is x = 1 & y = -4Given Equations-2x = 2 + y-6x - y = -2Derived Equations3 * (2+y) - y = -26 + 3y - y = -26 + 2y = -22y = -8y = -4-2x = 2 + (-4)-2x = -2x = 1Checking Answers-2 * (1) = 2 + (-4)-2 = -2-6 * (1) - (-4) = -2-6 + 4 = -2-2 = -2