(3x + 2)(x - 5) = 0 x = -2/3 or 5
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A quadratic equation is defined as an equation in which one or more of the terms ... In Geometry, we will concentrate on the graphical solutions to these systems. ... You can use the same table of values and simply find the y values for the straight line. ... Check (5,3) y = x2 - 4x - 2 3 = 52 - 4(5) - 2 3 = 3 check, y = x - 2 3 = 5 - 2
If: x = 2/3 and x = 5/7 Then: (3x-2)(7x-5) = 0 Equation: 21x2-29x+10 = 0
If: x-2y = 1 and 3xy -y^2 = 8 Then: x = 1+2y and 3(1+2y)y -y^2 = 8 Hence: 3y+6y^2 -y^2 = 8 => 5y^2 +3y -8 = 0 Solving the above quadratic equation: y =1 or y = -8/5 Solutions by substitution are: when y=1 then x=3 and when y=-8/5 then x=-11/5
(3x + 2)(x - 5) = 0 x = -2/3 or 5
There is one solution. To find it, divide both sides of the equation by 2. This leaves you with x=5, where 5 is your solution.
1st equation: x^2 -xy -y squared = -11 2nd equation: 2x+y = 1 Combining the the two equations together gives: -x^2 +3x +10 = 0 Solving the above quadratic equation: x = 5 or x = -2 Solutions by substitution: (5, -9) and (-2, 5)
x = 2 and x = -5
Equation: 10x^2 -29x +10 = 0 When factored: (2x-5)(5x-2) = 0 Its solutions: x = 5/2 or x = 2/5
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The solutions work out as: x = 52/11, y = 101/11 and x = -2, y = -11
(1,2) (0,5) (-1,8) (2,-1) (-2,11) All of these are solutions to the given equation.
There are no real solutions because the discriminant of the quadratic equation is less than zero.
It is a quadratic equation and its solutions are: x = 3 and x = 5
If you mean 5x^2 -7x +2 = 0 then it is a quadratic equation with solutions of x = 2/5 or x = 1
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