Most likeely.
8 2X4, any multiple of 8 say n8 2X4Xn and is therefore divisible by both 2 and 4
You can use any common multiple of 2 and 4. The easiest (for subsequent calculations) to use is the lowest common multiple, which for 2 and 4 is 4. → 1/2 = 2/4 → 3/4 = 3/4 (it already has 4 in the denominator)
2n where n is any positive integer. i.e. when n=1 multiple=2 when n=2 multiple=4 when n=3 multiple=6 etc..
Yes. By definition a multiple of 8 is any number that can be expressed as 8*n, where n is an integer. But 8n=4*(2*n), and 2*n is an integer, when n is an integer. Because 8n equals four times an integer, 8n is a multiple of 4.
Any multiple of 4 is also a multiple of 2.
Most likeely.
No. Any multiple of 4 is automatically also a multiple of 2. This is because 2 is, in turn, a factor of 4.
8 2X4, any multiple of 8 say n8 2X4Xn and is therefore divisible by both 2 and 4
4 and any multiple of 4
Any multiple of 20 is also a multiple of 4.
No, but vice versa holds true. Case and point: 6 is a multiple of 2, but not a multiple of 4. 8 is a multiple of 4, and is a multiple of 2. Because a factor of 4 is 2, every multiple of 4 is also a multiple of 2. But since 4 is not a factor of 2, rather, only half of it, only half of the multiples of 2 will be multiples of 4.
Any multiple of 4.
Any multiple of 36 is also a multiple of 4 and 9.
Because 2 is a factor of 4. If a number is a multiple of four, when you add that it is a multiple of 2 there is no extra information, no additional factor.
The least common multiple of 4 and 5 is 20. The least common multiple of 15 and 20 is 60. (Thus, the least common multiple of 4, 5, and 15 is 60.) Any multiple of 60 will also be a multiple of 4, 5, and 15.
Any multiple of 4.