No. One of the group axioms is that each element must have an inverse element. This is not the case with integers. In other words, you can't solve an equation like:
5 times "n" = 1
in the set of integers.
Yes
no
The set of positive integers does not contain the additive inverses of all but the identity. It is, therefore, not a group.
Any set where the result of the multiplication of any two members of the set is also a member of the set. Well known examples are: the natural numbers (ℕ), the integers (ℤ), the rational numbers (ℚ), the real numbers (ℝ) and the complex numbers (ℂ) - all closed under multiplication.
NO. Certainly not. Additive inverse and Multiplicative inverse doesn't exist for many elements.
No. The set does not include inverses.
No. The inverses do not belong to the group.
The set of integers, under addition.
The set of integers is not closed under multiplication and so is not a field.
To determine if a set is closed under multiplication, we need to check if the product of any two elements from the set is also an element of the same set. For example, the set of integers is closed under multiplication because the product of any two integers is always an integer. In contrast, the set of natural numbers is also closed under multiplication, while the set of rational numbers is closed under multiplication as well. However, sets like the set of positive integers and the set of even integers are also closed under multiplication.
Yes!
Yes!
Yes
They are not the same!The set of integers is closed under multiplication but not under division.Multiplication is commutative, division is not.Multiplication is associative, division is not.
Yes.
No, it is not.
Yes.