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What is the common difference in the following arithmetic sequence 12 6 0 -6 ...?
It appears to be -6
What is the sum of the first 12 terms of the arithmetic sequence?
The sum of the first 12 terms of an arithmetic sequence is: sum = (n/2)(2a + (n - 1)d) = (12/2)(2a + (12 - 1)d) = 6(2a + 11d) = 12a + 66d where a is the first term and d is the common difference.
What is the formula for the nth term of this sequence 17 29 41 53 65 77?
t(n) = 12*n + 5
What is the nth term of 12 19 26 33 40?
Well, honey, looks like we've got ourselves an arithmetic sequence here with a common difference of 7. So, to find the nth term, we use the formula a_n = a_1 + (n-1)d. Plug in the values a_1 = 12, d = 7, and n to get the nth term. Math doesn't have to be a drag, darling!
What is the d value of the following arithmetic sequence 16 9 2 5 12 19?
The sequence in the question is NOT an arithmetic sequence. In an arithmetic sequence the difference between each term and its predecessor (the term immediately before) is a constant - including the sign. It is not enough for the difference between two successive terms (in any order) to remain constant. In the above sequence, the difference is -7 for the first two intervals and then changes to +7.
What is the common difference in the following arithmetic sequence 12 6 0 -6 ...?
It appears to be -6
WHAT IS THE Th TERM IN AN ARITHMETIC SEQUENCE WHOSE Th TERM IS -25 AND HAS A COMMON DIFFERENCE -12?
-13
Is this sequence arithmetic If so, what is the common difference (d)12, 19, 26, 33?
yes, d = 7
What is the sum of the first 12 terms of the arithmetic sequence?
The sum of the first 12 terms of an arithmetic sequence is: sum = (n/2)(2a + (n - 1)d) = (12/2)(2a + (12 - 1)d) = 6(2a + 11d) = 12a + 66d where a is the first term and d is the common difference.
What is the formula for the nth term of this sequence 17 29 41 53 65 77?
t(n) = 12*n + 5
What is the nth term of 12 19 26 33 40?
Well, honey, looks like we've got ourselves an arithmetic sequence here with a common difference of 7. So, to find the nth term, we use the formula a_n = a_1 + (n-1)d. Plug in the values a_1 = 12, d = 7, and n to get the nth term. Math doesn't have to be a drag, darling!
What is the d value of the following arithmetic sequence 16 9 2 5 12 19?
The sequence in the question is NOT an arithmetic sequence. In an arithmetic sequence the difference between each term and its predecessor (the term immediately before) is a constant - including the sign. It is not enough for the difference between two successive terms (in any order) to remain constant. In the above sequence, the difference is -7 for the first two intervals and then changes to +7.
Is 3 6 12 24 48 an arithmetic sequence?
No, geometric, common ratio 2
Which explains why the sequence 216 12 23 is arithmetic or geometric?
The sequence 216 12 23 is neither arithmetic nor geometric.
What is the value of the nth term in the following arithmetic sequence 12 6 0 -6 ...?
To find the value of the nth term in an arithmetic sequence, you can use the formula: (a_n = a_1 + (n-1)d), where (a_n) is the nth term, (a_1) is the first term, (n) is the term number, and (d) is the common difference between terms. In this sequence, the first term (a_1 = 12) and the common difference (d = -6 - 0 = -6). So, the formula becomes (a_n = 12 + (n-1)(-6)). Simplifying this gives (a_n = 12 - 6n + 6). Therefore, the value of the nth term in this arithmetic sequence is (a_n = 18 - 6n).
The simple formula for the nth term of an arithmetic sequence is an equals 4n plus 16 What is the explicit formula corresponding to the simple formula?
The explicit formula for an arithmetic sequence is given by an = a1 + (n-1)d, where a1 is the first term and d is the common difference. In this case, the first term a1 is 16, and the common difference d is 4. Therefore, the explicit formula for the arithmetic sequence is an = 16 + 4(n-1) = 4n + 12.
Is 20 12 62 a geometric or arithmetic sequence?
It is neither.
