7
It appears to be -6
The sum of the first 12 terms of an arithmetic sequence is: sum = (n/2)(2a + (n - 1)d) = (12/2)(2a + (12 - 1)d) = 6(2a + 11d) = 12a + 66d where a is the first term and d is the common difference.
t(n) = 12*n + 5
Well, honey, looks like we've got ourselves an arithmetic sequence here with a common difference of 7. So, to find the nth term, we use the formula a_n = a_1 + (n-1)d. Plug in the values a_1 = 12, d = 7, and n to get the nth term. Math doesn't have to be a drag, darling!
The sequence in the question is NOT an arithmetic sequence. In an arithmetic sequence the difference between each term and its predecessor (the term immediately before) is a constant - including the sign. It is not enough for the difference between two successive terms (in any order) to remain constant. In the above sequence, the difference is -7 for the first two intervals and then changes to +7.
It appears to be -6
-13
yes, d = 7
An arithmetic sequence is a series of numbers in which each term is obtained by adding a constant value, called the common difference, to the previous term. In contrast, a geometric sequence is formed by multiplying the previous term by a constant value, known as the common ratio. For example, in the arithmetic sequence 2, 5, 8, 11, the common difference is 3, while in the geometric sequence 3, 6, 12, 24, the common ratio is 2. Thus, the primary difference lies in how each term is generated: through addition for arithmetic and multiplication for geometric sequences.
The sum of the first 12 terms of an arithmetic sequence is: sum = (n/2)(2a + (n - 1)d) = (12/2)(2a + (12 - 1)d) = 6(2a + 11d) = 12a + 66d where a is the first term and d is the common difference.
t(n) = 12*n + 5
No, the sequence 3, 6, 12, 24 is not an arithmetic sequence. In an arithmetic sequence, the difference between consecutive terms is constant. Here, the differences are 3 (6-3), 6 (12-6), and 12 (24-12), which are not the same. This sequence is actually a geometric sequence, as each term is multiplied by 2 to get the next term.
Well, honey, looks like we've got ourselves an arithmetic sequence here with a common difference of 7. So, to find the nth term, we use the formula a_n = a_1 + (n-1)d. Plug in the values a_1 = 12, d = 7, and n to get the nth term. Math doesn't have to be a drag, darling!
The sequence in the question is NOT an arithmetic sequence. In an arithmetic sequence the difference between each term and its predecessor (the term immediately before) is a constant - including the sign. It is not enough for the difference between two successive terms (in any order) to remain constant. In the above sequence, the difference is -7 for the first two intervals and then changes to +7.
No, geometric, common ratio 2
To find the value of the nth term in an arithmetic sequence, you can use the formula: (a_n = a_1 + (n-1)d), where (a_n) is the nth term, (a_1) is the first term, (n) is the term number, and (d) is the common difference between terms. In this sequence, the first term (a_1 = 12) and the common difference (d = -6 - 0 = -6). So, the formula becomes (a_n = 12 + (n-1)(-6)). Simplifying this gives (a_n = 12 - 6n + 6). Therefore, the value of the nth term in this arithmetic sequence is (a_n = 18 - 6n).
The sequence 216 12 23 is neither arithmetic nor geometric.