0
No, it is most definitely not. As long as they are not equal to zero
In the sum x-3 you have two components.
x (positive) and -3.
Likewise in 3-x you have:
3 and -x
However if both equal to 0 x will equal 3 in both sums.
In the context of your question, they are not the same.
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What is x3 3x-50?
3x=50
What is x3 plus 4x2-3x-12 divided by x2-3?
(x3 + 4x2 - 3x - 12)/(x2 - 3) = x + 4(multiply x2 - 3 by x, and subtract the product from the dividend)1. x(x2 - 3) = x3 - 3x = x3 + 0x2 - 3x2. (x3 + 4x2 - 3x - 12) - (x3 + 0x2 - 3x) = x3 + 4x2 - 3x - 12 - x3 + 3x = 4x2 - 12(multiply x2 - 3 by 4, and subtract the product from 4x2 - 12)1. 4x(x - 3) = 4x2 - 12 = 4x2 - 122. (4x2 - 12) - (4x2 - 12) = 4x2 - 12 - 4x2 + 12 = 0(remainder)
Factor by grouping 3-3x plus x2-x3?
3 - 3x + x2 - x3 = (1 - x)(x2 + 3)
How do you factor 3X to the third power plus 192?
3x3 + 192 3(x3 + 64) ========
What is the absolute value of 3x-5?
8
