No, it is most definitely not. As long as they are not equal to zero
In the sum x-3 you have two components.
x (positive) and -3.
Likewise in 3-x you have:
3 and -x
However if both equal to 0 x will equal 3 in both sums.
In the context of your question, they are not the same.
3x=50
(x3 + 4x2 - 3x - 12)/(x2 - 3) = x + 4(multiply x2 - 3 by x, and subtract the product from the dividend)1. x(x2 - 3) = x3 - 3x = x3 + 0x2 - 3x2. (x3 + 4x2 - 3x - 12) - (x3 + 0x2 - 3x) = x3 + 4x2 - 3x - 12 - x3 + 3x = 4x2 - 12(multiply x2 - 3 by 4, and subtract the product from 4x2 - 12)1. 4x(x - 3) = 4x2 - 12 = 4x2 - 122. (4x2 - 12) - (4x2 - 12) = 4x2 - 12 - 4x2 + 12 = 0(remainder)
3 - 3x + x2 - x3 = (1 - x)(x2 + 3)
3x3 + 192 3(x3 + 64) ========
8
2x3 - 7 + 5x - x3 + 3x - x3 = 8x - 7
3x=50
(x3 + 4x2 - 3x - 12)/(x2 - 3) = x + 4(multiply x2 - 3 by x, and subtract the product from the dividend)1. x(x2 - 3) = x3 - 3x = x3 + 0x2 - 3x2. (x3 + 4x2 - 3x - 12) - (x3 + 0x2 - 3x) = x3 + 4x2 - 3x - 12 - x3 + 3x = 4x2 - 12(multiply x2 - 3 by 4, and subtract the product from 4x2 - 12)1. 4x(x - 3) = 4x2 - 12 = 4x2 - 122. (4x2 - 12) - (4x2 - 12) = 4x2 - 12 - 4x2 + 12 = 0(remainder)
3 - 3x + x2 - x3 = (1 - x)(x2 + 3)
x3 + x2 - 3x - 3 x(x2 + x - 3) - 3
3 ln(x) = ln(3x)ln(x3) = ln(3x)x3 = 3xx2 = 3x = sqrt(3)x = 1.732 (rounded)
No, (3x) and (x^3) are not the same. (3x) represents three times the value of (x), while (x^3) (or (x) cubed) represents (x) multiplied by itself three times. For example, if (x = 2), then (3x = 6) and (x^3 = 8), which are clearly different values.
If 3x = 81 then x = 27 and 27 cubed = 19683
3/x2
4X2+X3+3X+7Y+2X3 can only be simplified to 3X3+4X2+3X+7Y, because X3 and 2X3 are the only like terms.
No. 3X is multiple (3 x X) X3 is exponential (X x X x X)
(x - 3)(x2 + 3x + 3)